The segment drawn from a vertex in a triangle to the midpoint of the opposite side.
2 answers:
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This problem can be completed in 2 ways. Both are acceptable.
Option 1:
This is an isosceles trapezoid that can be divided into a rectangle and two congruent triangles.
The area of the rectangle is the base times the height.
The area of one of the triangles is half the base times the height.
The other triangle must have that area too.
The area is 56 square centimeters.
Option 2:
We can use the area formula for the trapezoid.
Where
is the length of the shorter base
and
is the length of the longer base
and
is the height.
The length of the shorter base is 9.
The length of the longer base is 9+5+5, or 19.
The height is 4.
Same answer. The area is 56 square centimeters.
Both options are two acceptable ways the problem can be tackled.
Option 1:
This is an isosceles trapezoid that can be divided into a rectangle and two congruent triangles.
The area of the rectangle is the base times the height.
The area of one of the triangles is half the base times the height.
The other triangle must have that area too.
The area is 56 square centimeters.
Option 2:
We can use the area formula for the trapezoid.
Where
and
and
The length of the shorter base is 9.
The length of the longer base is 9+5+5, or 19.
The height is 4.
Same answer. The area is 56 square centimeters.
Both options are two acceptable ways the problem can be tackled.
Answer:
We know that ,
Number of zeroes in a polynomial = degree of the polynomial
( degree of polynomial = the highest power in the polynomial )
therefore ,
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