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3 years ago

The segment drawn from a vertex in a triangle to the midpoint of the opposite side.

Mathematics

2 answers:

Kipish [7]3 years ago

5 0

Answer:

It is Median

Step-by-step explanation:

AVprozaik [17]3 years ago

3 0

check the picture below.

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Is 7,24,25 form a right angle

NikAS [45]

Yes it does.
A and B are *2
That will be C *2 + D *2 is gonna be
a right triangle of 7,24,25

3 0

3 years ago

Explain in words how to find the product of -4 (-1.5) using a number line.where do you end up

Ierofanga [76]

Answer:

To multiply two minus numbers they will result as a positive number.

the product of any numbers when there is a negtive will always have 2 negtives invlved form three numbers including the answer.

-4 x -1.5 is the same as 4 x 1.5

the answer is 6

Three numbers like -1 x 4 will also be 2 numbers of negative.

= -4

We change this to -4 x 1.5 and shows the answer as -6

But the question had 2 negative numbers already and the answer is just positive 6.

8 0

2 years ago

Read 2 more answers

It is estimated that 0.54 percent of the callers to the Customer Service department of Dell Inc. will receive a busy signal. Wha

stira [4]

Using the binomial distribution, it is found that there is a 0.8295 = 82.95% probability that at least 5 received a busy signal.

<h3>What is the binomial distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem:

0.54% of the calls receive a busy signal, hence p = 0.0054.

A sample of 1300 callers is taken, hence n = 1300.

The probability that at least 5 received a busy signal is given by:

$P(X \geq 5) = 1 - P(X < 5)$

In which:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4).

Then:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{1300,0}.(0.0054)^{0}.(0.9946)^{1300} = 0.0009$

$P(X = 1) = C_{1300,1}.(0.0054)^{1}.(0.9946)^{1299} = 0.0062$

$P(X = 2) = C_{1300,2}.(0.0054)^{2}.(0.9946)^{1298} = 0.0218$

$P(X = 3) = C_{1300,3}.(0.0054)^{3}.(0.9946)^{1297} = 0.0513$

$P(X = 4) = C_{1300,4}.(0.0054)^{4}.(0.9946)^{1296} = 0.0903$

Then:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0009 + 0.0062 + 0.0218 + 0.0513 + 0.0903 = 0.1705.

$P(X \geq 5) = 1 - P(X < 5) = 1 - 0.1705 = 0.8295$

0.8295 = 82.95% probability that at least 5 received a busy signal.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

6 0

1 year ago

what is the unknown number in sequence 2 in the chart? What rule can you write that relates sequence 2 to sequence 1

sergij07 [2.7K]

Answer C. The pattern is that each number in sequence 1 is being doubled to get the number in sequence 2, and 40*2=80

3 0

2 years ago

I neeed this now asap

son4ous [18]

Answer:

What type of math this is text me back!

Step-by-step explanation:

3 0

1 year ago