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Lostsunrise [7]

3 years ago

5

Solve for x: 5x + 4z = 10z - 2x

2 answers:

Digiron [165]3 years ago

5 0

Answer:

x= 6/7z

Step-by-step explanation:

5x + 4z = 10z - 2x

5x + 2x = 10z - 4z

7x = 6z

x = 6/7z

Tanzania [10]3 years ago

3 0

Answer: 5x + 4z = 10z - 2x

move variable to the left side and change its sign

5x + 2x + 4z +10

Move variable to the right side and change its sign. 5x + 2x = 10z - 4z Collect the like terms 5x + 2x =10z - 4z ↓ 7x = 10z - 4z Collect the like terms ↓ 7x = 6z Divide both sides of the equation by 7 x = 6/7 z decimal <em>0.857143</em>

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Step-by-step explanation:

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What is the answer to 1/7(x+3/4)=1/8

ivolga24 [154]

Answer:

<h3>x = 1/8</h3>

Step-by-step explanation:

1/7(x+3/4) = 1/8

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3 0

3 years ago

What is the solution to he equation (y/y-4)-(4/y+4)=3^2/y^2-16

kicyunya [14]

Answer:

$y=\pm i \sqrt{7}$

Step-by-step explanation:

Given equation is $\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{3^2}{(y^2-16)}$

Factor denominators then solve by making denominators equal

$\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{3^2}{(y^2-16)}$

$\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{9}{(y+4)\left(y-4\right)}$

$\frac{y\left(y+4\right)-4\left(y-4\right)}{\left(y-4\right)\left(y+4\right)}=\frac{9}{(y+4)\left(y-4\right)}$

$y\left(y+4\right)-4\left(y-4\right)=9$

$y^2+4y-4y+16=9$

$y^2=9-16$

$y^2=-7$

take squar root of both sides

$y=\pm \sqrt{-7}$

$y=\pm i \sqrt{7}$

Hence final answer is $y=\pm i \sqrt{7}$ .

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