$W = \displaystyle \int^{5}_{2} F(x) ~ dx\\\\\\= \displaystyle \int^{5}_{2} \left(12x^2 +7\right) ~dx\\\\\\= 12\displaystyle \int^{5}_{2} x^2 ~dx + \displaystyle \int^{5}_{2} 7~ dx\\\\\\=12 \left[\dfrac{x^3}3 \right]^{5}_{2} + 7\left[x\right]^{5}_{2}\\\\\\=4(5^3-2^3) + 7(5-2) = 468 + 21 = 489~ J$

5 0

2 years ago

Hey :)

Slav-nsk [51]

Vertex = (3, 5)
focus = (3, 7)
directrix is y = 3

8 0

2 years ago

Read 2 more answers

In triangle STU, s = 9 cm, t = 15 cm, and m angle U = 37 degrees. Find u.

liq [111]

We can solve the length of u using Laws of Cosine since we are given with lengths of two side and one angle.
The solution is shown below:
cos U =( s²+t²-u²)/2st
cos 37°= (9²+15²-u²)/2*9*15
0.79863*270=306-u²
u²=306-215.63
u=9.5 units
Therefore, the length of u is 9.5cm.

4 0

3 years ago

Read 2 more answers