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stepladder [879]
3 years ago
8

Camryn practices the trumpet every 11^\text{th}11

Mathematics
2 answers:
Pie3 years ago
6 0

Answer:

33 days

Step-by-step explanation:

Snowcat [4.5K]3 years ago
4 0

Answer:

in 33 days

Step-by-step explanation:

Trumpet practice is every 11 days. Flute practice is every 3 days.

You need the Least Common Multiple (the LCM) of the two numbers, 3 and 11.

Since 3 and 11 are prime, the LCM of 3 and 11 is their product.

LCM = 3 * 11 = 33

Answer: in 33 days

You can also solve this by listing multiples of 3 and 11 until you find the smallest number that is a multiple of both 3 and 11.

Multiples of 3: 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, ...

Multiples of 11: 11, 22, 33, 44, ...

The smallest multiple of both 3 and 11 is the smallest number that shows in both lists. It is 33.

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F(x) = 3x-1 , (f of g)(x) = x^2 , Find g(x)
fomenos

Answer:

g(x)=\dfrac{x^2+1}{3}

Step-by-step explanation:

<u>Given functions</u>:

\begin{cases}f(x)=3x-1\\(f \circ g)(x)=x^2\end{cases}

Composite functions are when the <u>output</u> of one function is used as the <u>input</u> of another.

Therefore, the given <u>composite function</u> (f o g)(x) means to <u>substitute</u> function g(x) in place of the x in function f(x).

\begin{aligned}(f \circ g)(x) & = x^2\\f(g(x)) & = x^2\\\implies 3(g(x))-1 & = x^2\\3(g(x))-1+1 & = x^2+1\\3(g(x))&=x^2+1\\\dfrac{3(g(x))}{3}&=\dfrac{x^2+1}{3}\\\implies g(x)&=\dfrac{x^2+1}{3}\end{aligned}

Therefore:

\boxed{g(x)=\dfrac{x^2+1}{3}}

6 0
1 year ago
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Answer:

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Step-by-step explanation:

8 0
3 years ago
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