For the following conditional statement, write the a.)

So,some please help me with this question !

Tamiku [17]

$\qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star$

$\qquad❖ \: \sf \: \angle C = 63 \degree$

$\textsf{ \underline{\underline{Steps to solve the problem} }:}$

$\qquad❖ \: \sf \:x + 4x + 12 + x=180°$

( Angle EBA= Angle DBC, and the three angles sum upto 180° due to linear pair property )

$\qquad❖ \: \sf \:6x + 12 = 180$

$\qquad❖ \: \sf \:6x = 180 - 12$

$\qquad❖ \: \sf \:6x = 168$

$\qquad❖ \: \sf \:x = 28 \degree$

Next,

$\qquad❖ \: \sf \: \angle C + \angle D + x = 180°$

$\qquad❖ \: \sf \: \angle C +3x + 5 + x = 180°$

$\qquad❖ \: \sf \: \angle C +4x = 180 - 5$

$\qquad❖ \: \sf \: \angle C +4(28) = 175$

( x = 28° )

$\qquad❖ \: \sf \: \angle C +112 = 175$

$\qquad❖ \: \sf \: \angle C = 175 - 112$

$\qquad❖ \: \sf \: \angle C = 63 \degree$

$\qquad \large \sf {Conclusion} :$

$\qquad❖ \: \sf \: \angle C = 63 \degree$

4 0

1 year ago

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A display case of wallets are marked 32 for $5. If Tim has $80, how many wallets can Tim get? (Assume no tax or other fees.)

Levart [38]

1 wallet= 5/32= 0.15625
Wallets for $80= 0.15625*80=12 wallets

7 0

2 years ago

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1. Find the area of the triangle. Show as much work as possible for full credit.

Ugo [173]

Answer:

A = 5/12 x^2

Step-by-step explanation:

A = 1/2 bh

The base is 5/6x and the height is x

A = 1/2 (5/6x) *x

A = 5/12 x^2

5 0

3 years ago

In which quadrant is the value of the x-coordinate of a point on the unit circle always greater than the y-coordinate?

Yuliya22 [10]

Answer:

IV

In the fourth quadrant (IV).

Step-by-step explanation:

In the IV quadrant the x coordinate is always positive and the y coordinate is always negative. So the x coordinate is always larger than the y coordinate.

4 0

1 year ago

A random sample of 144 recent donations at a certain blood bank reveals that 81 were type A blood. Does this suggest that the ac

Reptile [31]

Answer:

Null hypothesis: $p=0.4$

Alternative hypothesis: $p \neq 0.4$

$z=\frac{0.5625 -0.4}{\sqrt{\frac{0.4(1-0.4)}{144}}}=3.98$

$p_v =2*P(z>3.98)=0.0000689$

Since the p value is very low compared to the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true percent of people with type A of blood is significantly different from 0.4 or 40%

Step-by-step explanation:

Information given

n=144 represent the random sample taken

X=81 represent the number of people with type A blood

$\hat p=\frac{81}{144}=0.5625$ estimated proportion of people with type A blood

$p_o=0.4$ is the value that we want to verify

$\alpha=0.01$ represent the significance level

z would represent the statistic

$p_v{/tex} represent the p value Hypothesis to testWe want to test if the percentage of the population having type A blood is different from 40%.: Null hypothesis:[tex]p=0.4$

Alternative hypothesis: $p \neq 0.4$

the statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info given we got:

$z=\frac{0.5625 -0.4}{\sqrt{\frac{0.4(1-0.4)}{144}}}=3.98$

Now we can calculate the p value with this probability taking in count the alternative hypothesis:

$p_v =2*P(z>3.98)=0.0000689$

Since the p value is very low compared to the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true percent of people with type A of blood is significantly different from 0.4 or 40%

3 0

3 years ago