Question

In the diagram, point O is the center of the circle. If m∠ABC = 70°, what is m∠AOC ?

Answer 1

Answer:

Step-by-step explanation:

Alright, lets get started.

Please refer the diagram I have attached.

Let us suppose angle ABO = x and angle CBO = y, so,

$x+y=70$

AO and BO will be same as both are radius.

Similarly, CO nd BO will be same as both are radius.

angle AOB = $180-x-x=180-2x$

angle COB = $180-y-y=180-2y$

Angle AOC = $360-(AOB+COB)=360-(180-2x+180-2y)=360-360+2(x+y)$

Angle AOC = $2(x+y)$

Putting the value of (x+y) as 70, then

$Angle AOC = 2*70=140$

So te answer is 140°    :    Answer

Hope it will help :)

Answer 2

The answer is 140 ,on plato also