Hello here is a solution :
<span> the radius of the circle is OA A(5;-12) and O (0;0)
OA= </span><span> square root ((5-0)² + (-12-0)²)
</span> = <span> square root (25+144)
</span> = <span> square root(169)
</span> OA = 13
Answer:
No, they can't be the same price
Step-by-step explanation:
There is not a way for them to cost the same amount because they are the same cost per topping.
Hope this helped! :)
Answer:
![\left( fg\right) \left( x\right) =2x^3\sqrt[3]{x}\\\\\left( \frac{f}{g} \right) \left( x\right) =\frac{2x^{3}}{\sqrt[3]{x} }](https://tex.z-dn.net/?f=%5Cleft%28%20fg%5Cright%29%20%20%5Cleft%28%20x%5Cright%29%20%20%3D2x%5E3%5Csqrt%5B3%5D%7Bx%7D%5C%5C%5C%5C%5Cleft%28%20%5Cfrac%7Bf%7D%7Bg%7D%20%5Cright%29%20%20%5Cleft%28%20x%5Cright%29%20%20%3D%5Cfrac%7B2x%5E%7B3%7D%7D%7B%5Csqrt%5B3%5D%7Bx%7D%20%7D)
Step-by-step explanation:
Answer:
pq= 12 cm
Step-by-step explanation:
8. D: The <em>longest sides of the quadrilaterals are 30 and 10</em>. That is a 30 : 10 ratio, which simplifies to <em>3 : 1, or </em>3/1. It's not 1 : 3 because it is the ratio between the large (comes first) to the small (comes second) figure.
9. B: <em>x corresponds to 26</em>, and from the previous problem, we figured out that <em>the sides of the larger figure are 3 times larger than the corresponding one on the smaller one</em>. So <em>x is 1/3 the length of 26</em>, which is 26/3.
