Question

This circle is centered at the point (3, 2), and the length of its radius is 5. What

Answer 1

Answer:

There is no  corrrect option given but the correct answer is below may help you.

Therefore,

Equation of Circle is

[te](x-3)^{2}+(y-2)^{2}=25[/tex]

Step-by-step explanation:

Given:

Let center be C,

$C(h,k)=(3,2)$

$Radius = r = 5$

To Find:

Equation of Circle = ?

Solution:

The Equation of Circle with center (h , k) and radius r is given as

$(x-h)^{2}+(y-k)^{2}=r^{2}$

Substituting the values we get

$(x-3)^{2}+(y-2)^{2}=5^{2}\\\\(x-3)^{2}+(y-2)^{2}=25$

Therefore,

Equation of Circle is

[te](x-3)^{2}+(y-2)^{2}=25[/tex]