All categories

3 years ago

Need help on questions 5-8 with work and answers plz i will really be very greatful

Mathematics

1 answer:

Leya [2.2K]3 years ago

8 0

Im not sure cuz i learned this for long time ago
but i think 5 is 1
and 7 might be2
i have no idea for 8
im sorry :/

You might be interested in

What is two other forms to the number 100,203

SIZIF [17.4K]

$100,203=1.00203\times10^5\\\\100,203=100,000+200+3\\\\100,203=1\times10^5+2\times10^2+3\times10^0$

4 0

3 years ago

Simplify: 4 square root of 2 plus square root of 32 minus square root of 16

VMariaS [17]

$4\sqrt{2}+\sqrt{32}-\sqrt{16}=4\sqrt{2}+4\sqrt{2}-4=8\sqrt{2}-4$

5 0

2 years ago

Consider the statement: For all integers n, if n3 is even then n is even. a. Explicitly write out what you are supposing and wha

Fittoniya [83]

Answer:

It is proved that if $n^3$ is even the n is even.

Step-by-step explanation:

Given n is any integer.

To show $n^3$ is even then n is even.

Proving by contrapositive suppose $n^3$ is odd. Then we need to show n is odd.

Then, letting k is a ny integer,

$n^3=2k+1\implies n=(2k+1)^{\frac{1}{3}}$

Now since (2k+1) is odd therefore n is odd.

Conversly let n is odd, then,

$n=2k+1\implies n^3=(2k+1)^3$

since 2k+1 is odd so $n^3$ is odd.

This proves, if n is even then $n^3$ is even.

4 0

3 years ago

(ab+3)^2 find the product

Alenkasestr [34]

Answer :

(ab+3)2

Steps :

Final result :

(ab + 3)2

Step by step solution :

Step 1 :

Final result :

(ab + 3)2

8 0

2 years ago

Um can someone help please and <br> thanks

Hitman42 [59]

You can use the pythagorean theorem
15^2 = 225
17^2 = 289
225 + b^2 = 289
b^2 = 64
b = 8

so one half of one side is 8 so the whole side would be 16

hope this helps

3 0

3 years ago