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h(x) = x³ - 2x² - 3x
The question you need to ask yourself is "How do you find the zeros of a function.
Answer: To find the zeros of a function, just set the function equal to zero then solve for x
x³ - 2x² - 3x = 0
Factor the left sides
x(x + 1)(x - 3) = 0
Now we can set factors equal to 0
x = 0 or x + 1 = 0 or x - 3 = 0
x = 0 or x = 0 - 1 or x = 0 + 3
x = 0 or x = -1 or x = 3
Thus,
The zeros of the function are: x = 0 or x = -1 or x = 3
As always, I am glad to help students like you!
Answer:
Solution: x = 2, y = -1 or (2, -1)
Step-by-step explanation:
Equation 1: 2x + y = 3
Equation 2: 5x - 2y = 12
Using the substitution method:
Transform the Equation 1 into its slope-intercept form:
2x + y = 3
2x - 2x + y = -2x + 3
y = 2x + 3
Substitute the value of y = -2x + 3 into Equation 2:
5x - 2y = 12
5x - 2(-2x + 3) = 12
5x + 4x - 6 = 12
9x - 6 = 12
9x - 6 + 6 = 12 + 6
9x = 18
9x/9 = 18/9
x = 2
Substitute the value of x = 2 into Equation 2 to solve for y:
5x - 2y = 12
5(2) - 2y = 12
10 - 2y = 12
10 - 10 - 2y = 12 - 10
-2y = 2
-2y/-2 = 2/-2
y = -1
Double-check whether the values for x and y will provide a true statement for both equations:
Equation 1: 2x + y = 3
2(2) + (-1) = 3
4 - 1 = 3
3 = 3 (True statement)
Equation 2: 5x - 2y = 12
5(2) - 2(-1) = 12
10 + 2 = 12
12 = 12 (True statement)
Therefore, the correct answers are: x = 2; y = -1 or (2, -1).
42 - 6 = 36 - 1
36 - 6 = 30 - 2
30 - 6 = 24 - 3
24 - 6 = 18 - 4
18 - 6 = 12 - 5
12 - 6 = 6 - 6
6 - 6 = 0 - 7
42/6 = 7
Think about it do you think it's subtraction or addition?
Answer:
b and e
Step-by-step explanation:
