3 years ago

Lim x^77-1 overx-1 at x approches 1

Mathematics

1 answer:

vagabundo [1.1K]3 years ago

6 0

$\displaystyle\lim_{x\to1}\frac{x^{77}-1}{x-1}=\lim_{x\to1}(x^{76}+x^{75}+\cdots+x^2+x+1)=77$

You might be interested in

|2/3-3/2|3^2-17/3 a)11/16 b)11/6 c)79/6 d)83/6

vfiekz [6]

Answer: The correct answer is: [B]:

____________________________________

→ " $\frac{11}{6}$ " .

____________________________________________

Explanation:

We are asked to solve: |2/3-3/2|3^2-17/3 ;

Let's rewrite this problem as:

____________________________________________

Simplify:

" | $\frac{2}{3} - \frac{3}{2}$ | * $3^{2} - \frac{17}{3}$ | " ;

____________________________________________

7 0

3 years ago

I got -4 but I don't see it on here, did I do something wrong??

Ira Lisetskai [31]

Answer:

it is -4

Step-by-step explanation:

but the answer is not on there so the answer will be D.

5 0

3 years ago

Read 2 more answers

Is 5/6 x 2/3 equal to greater than or less than 2/3

viva [34]

Greater than obviously

7 0

3 years ago

Read 2 more answers

Problem 5.A miner is trapped inside a mine and has access to 3 doors. The first door leads to a tunneland can take him to safety

Likurg_2 [28]

Answer:

Expected time is 15 hours for him to get to safety.

Step-by-step explanation:

We define X as the time that this miner would get to safety.

We define Y as the door he chooses initially.

P(Y= 1) = P(Y=2)=P(Y=3) = 1/3

We have E[X|Y=1] = 3

E[X|Y] = 5 hours + E[X}

E[X|Y] = 7 hours + E[X]

Then we have

E[X] = 1/3(3 + 5 + E[X] + 7 + E[X])

We cross multiply

3*E[X] = (15 + 2E[x])

3E[X] - 2E[X] = 15

E[X] = 15

So the time it would take to get him to safety is 15 hours

5 0

3 years ago

Write the following in expanded exponential form a. 30405

lana [24]

Answer:

30000+0+400+0+5

6000000+800000+0+4000+100+50+2

Step-by-step explanation:

hope it's right plz mark me brainlists

7 0

2 years ago