All categories

3 years ago

Lim x^77-1 overx-1 at x approches 1

Mathematics

1 answer:

vagabundo [1.1K]3 years ago

6 0

$\displaystyle\lim_{x\to1}\frac{x^{77}-1}{x-1}=\lim_{x\to1}(x^{76}+x^{75}+\cdots+x^2+x+1)=77$

You might be interested in

HELP PLS QUICK MIGHT GIVE BRAINLIST ONLY IF 2 PEOPLE ANSWER!

Afina-wow [57]

Answer:

area = 10 squares units

if points changes

5 0

3 years ago

What is -a^-2 if a = -5? (PLEASE HELP WILL MARK BRAINLIEST!!!)

4vir4ik [10]

Answer:

-1/25

Step-by-step explanation:

-a^-2

-(-5)^-2

=-1/25

6 0

3 years ago

Use the number line to show<br> 2/3 divide 1/12 <br> What is the quotient

JulsSmile [24]

Answer:

Step-by-step explanation:

There is no number line given, so I will use the "keep change flip" method.

$\frac{2}{3}\div\frac{1}{2}\\\rule{150}{0.5}\\ \frac{2}{3}\cdot\frac{12}{1}\\\\\frac{2\cdot12}{3\cdot1}\\\\\frac{24}{3}\\\\\boxed{8}$

Hope this helps.

4 0

3 years ago

Read 2 more answers

The perimeter of the triangular park shown on the right is 11x - 7. What is the missing length?

AysviL [449]

Answer:

6x-4

Step-by-step explanation:

the perimeter is the distance around the shape, we get this by adding all the sides, call the missing side y and set up an equation for the perimeter

11x-7 = 4x+2 + x-5 + y

solve for y

11x-7 = 5x -3 + y

11x-4 = 5x + y

6x-4 = y

4 0

3 years ago

Describe the translation. y = (x-5)squared +5 - y = (x-))squared +0

vovangra [49]

In functions; translations are used to move lines, points or shapes across the graph (i.e. up, down, right or left).

The translation from $y = (x - 5)^2 +5$ to $y = (x - 0)^2 +0$ is to shift $y = (x - 5)^2 +5$ to the left by 5 units and then downward by 5 units

The given parameters are:

$y = (x - 5)^2 +5$

$y = (x - 0)^2 +0$

Assume the first point is: $y = (x - 5)^2 +5$

While the second is: $y = (x - 0)^2 +0$

The first point is first shifted left by 5 units

The rule to this translation is: $(x,y) \to (x + 5,y)$

So, we have:

$y' = (x - 5 + 5)^2 + 5$

$y' = (x - 0)^2 + 5$

Next, the resulting function is shifted down by 5 units.

The rule to this translation is: $(x,y) \to (x,y- 5)$

So, we have:

$y" = y' - 5$

This gives:

$y" = (x - 0)^2 + 5 - 5$

$y" = (x - 0)^2 + 0$

Hence, the translation from $y = (x - 5)^2 +5$ to $y = (x - 0)^2 +0$ is to shift $y = (x - 5)^2 +5$ to the left by 5 units and then downward by 5 units