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Novosadov [1.4K]

4 years ago

11

All the members of a construction crew work at the same pace. Four of them working together are able to pour concrete foundation

s in 32 hours. How many hours would this job take if the number of workers:
Increased 2 times

Increased 4 times

1 answer:

Ira Lisetskai [31]4 years ago

3 0

Answer:

1) Increased by 2 times then 16 hours

2) Increased by 4 times then 8 hours

Step-by-step explanation:

Given :-

<em>==> 4 construction crew members need 32 hours to pour concrete foundations.</em>

<em>==> All the members work at a same pace.</em>

1) If the numbers of workers are increased by 2 time i.e., 4 workers × 2 = 8 workers. It would take half of the time that is taken now i.e., 32 hours ÷ 2 = 16 hours.

2) If the numbers of workers are increased by 4 time i.e., 4 workers × 4 = 16 workers. It would take 1/4th of the time that is taken now i.e., 32 hours ÷ 4 = 8 hours.

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Step-by-step explanation:

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3 years ago

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Inessa05 [86]

In this problem, you combine the like terms...

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3 years ago

Find the values of x and y that makes these triangles congruent by HL.

crimeas [40]

Answer:

What is HL? holey logic? hawk a loogy? half lies? honey lemon? heavenly lampshade? hand lotion?

Step-by-step explanation:

as AB = DE, the only options given where x = y - 1 are the the second and third.

as AC and AD are equal from ASA

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4 0

3 years ago

Rina8888 [55]

To solve this we are going to use the formula for speed: $S= \frac{d}{t}$
where
$S$ is the speed
$d$ is the distance
$t$ is the time

Let $S_{l}$ be the speed of the boat in the lake, $S_{a}$ the speed of the boat in the river, $t_{l}$ the time of the boat in the lake, and $t_{a}$ the time of the boat in the river.

We know for our problem that <span>the current of the river is 2 km/hour, so the speed of the boat in the river will be the speed of the boat in the lake minus 2km/hour:
</span> $S_{a}=S_{l}-2$
We also know that in the lake the boat<span> sailed for 1 hour longer than it sailed in the river, so:
</span> $t_{l}=t_{a}+1$
<span>
Now, we can set up our equations.
Speed of the boat traveling in the river:
</span> $S_{a}= \frac{6}{t_{a} }$
But we know that $S_{a}=S_{l}-2$ , so:
$S_{l}-2= \frac{6}{t_{a} }$ equation (1)

Speed of the boat traveling in the lake:
$S_{l}= \frac{15}{t_{l} }$
But we know that $t_{l}=t_{a}+1$ , so:
$S_{l}= \frac{15}{t_{a}+1}$ equation (2)

Solving for $t_{a}$ in equation (1):
$S_{l}-2= \frac{6}{t_{a} }$
$t_{a}= \frac{6}{S_{l}-2}$ equation (3)

Solving for $t_{a}$ in equation (2):
$S_{l}= \frac{15}{t_{a}+1}$
$t_{a}+1= \frac{15}{S_{l}}$
$t_{a}=\frac{15}{S_{l}}-1$
$t_{a}= \frac{15-S_{l}}{S_{l}}$ equation (4)

Replacing equation (4) in equation (3):
$t_{a}= \frac{6}{S_{l}-2}$
$\frac{15-S_{l}}{S_{l}}=\frac{6}{S_{l}-2}$

Solving for $S_{l}$ :
$\frac{15-S_{l}}{S_{l}}=\frac{6}{S_{l}-2}$
$(15-S_{l})(S_{l}-2)=6S_{l}$
$15S_{l}-30-S_{l}^2+2S_{l}=6S_{l}$
$S_{l}^2-11S_{l}+30=0$
$(S_{l}-6)(S_{l}-5)=0$
$S_{l}=6$ or $S_{l}=5$

We can conclude that the speed of the boat traveling in the lake was either 6 km/hour or 5 km/hour.

3 0

4 years ago

:::::::::::::::::::bdisbsidvwish

Wewaii [24]

Answer:

what you are looking for is the exact form which is 71 over 12

I hope this helps you!

(p.s can I please have brainlyest?)

Step-by-step explanation

Exact form: 71/12

Decimal form: 5.916

Mixed number: 5 11/12

4 0

3 years ago