<h3>
Answer: 5/51</h3>
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Explanation:
We have 6 green out of 6+6+6 = 18 total
The probability of getting green is 6/18 = 1/3.
After selecting that green jelly bean and not putting it back, we have 6-1 = 5 green out of 18-1 = 17 total.
The probability of selecting another green is 5/17.
Multiply the two fractions 1/3 and 5/17
(1/3)*(5/17) = (1*5)/(3*17) = 5/51
The probability of selecting two greens in a row is 5/51 where we do not put the first selection back. We also do not replace the green jelly bean with some other identical copy.
Note: 5/51 = 0.098039 approximately
Box and whiskers plots use five number summaries. The first number is:
1:Minimum
2.Quartile 1
3.Mean
4.Quartile 2
5.maximum
Quartile are simple to get.
If your set of numbers is:
2,3,3,6,8,8,11
Then find the mean
2 3 3 |6| 8 8 11
Find the mean of the left side of of mean.
2 |3| 3 3 =Quartile 1
Then the right side
8 |8| 11 8 =Quartile 2
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Your 5 number summary is 2,3,6,8,11
Plot them on the number line, but put a line above where the dot would go. take the 3 middle lines and connect to make a box. The lines on the outside of the box are the whiskers, AKA distributed data.
y=-2
Step-by-step explanation:
if line has zero slope (b) it means that b is undefined.
if x=0 y=-2 because line has no slope. so b=-2
y=-2
Answer:
8
Step-by-step explanation:
Ham with or without cheese-2 choices
Bologna with or without cheese-2 choices
Bologna with cheese with water or juice-2 choices
Bologna without cheese with juice or water-2 choices
Ham with cheese with juice or water -2 choices
Ham without cheese with juice or water -2 choices
2+2+2+2=8
Kile has 8 choices for lunch
Answer:
Step-by-step explanation:
We have been given two expressions 
and
Now we need to find out least common multiple of these two expressions.
First we need to find out what is common factor of both expressions. and
Least common multiple means find the expression which can be divided by both expressions.
15 and 6 both goes into 30
so 30 is part of LCM (least common multiple )
Now pickup the highest exponent of each variable.
So we get 
Hence required least common multiple is
