The correct solution is 75.
40=6.95c+5.25
The $40 is what you want it all to equal, so that goes to one side by itself.
The CDs are 6.95 each, so they get a variable to show that.
The 5.95 is added to that, showing that it's only charged once.
Then, all you have to do is solve for c, which is the number of CD's you can buy.
Answer:
confidence level is missing
Step-by-step explanation:
<em>1.confidence level </em>
The results can be given only in a predetermined confidence level
<em>2. point estimate</em>
The illustration states the estimate 26% of the professionals who interview job applicants said the biggest interview turnoff is that the applicant did not make an effort to learn about the job or the company.
<em>3.sample size</em>
Sample size is given as 1910 people
<em>4.confidence interval </em>
Confidence interval is given ±3 around the point of estimate
Answer:
x=9
Step-by-step explanation:
Step 1: Simplify by both sides of the equation.
80-3x=53
80+-3x=53
-3x+80=53
Step 2: Subtract 80 from both sides.
-3x+80-80=53-80
-3x=-27
Step 3: Divide by both sides by 3.
-3x/-3 = -27/-3
x=9
Answer: ![3x^2y\sqrt[3]{y}\\\\](https://tex.z-dn.net/?f=3x%5E2y%5Csqrt%5B3%5D%7By%7D%5C%5C%5C%5C)
Work Shown:
![\sqrt[3]{27x^{6}y^{4}}\\\\\sqrt[3]{3^3x^{3+3}y^{3+1}}\\\\\sqrt[3]{3^3x^{3}*x^{3}*y^{3}*y^{1}}\\\\\sqrt[3]{3^3x^{2*3}*y^{3}*y}\\\\\sqrt[3]{\left(3x^2y\right)^3*y}\\\\\sqrt[3]{\left(3x^2y\right)^3}*\sqrt[3]{y}\\\\3x^2y\sqrt[3]{y}\\\\](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27x%5E%7B6%7Dy%5E%7B4%7D%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B3%5E3x%5E%7B3%2B3%7Dy%5E%7B3%2B1%7D%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B3%5E3x%5E%7B3%7D%2Ax%5E%7B3%7D%2Ay%5E%7B3%7D%2Ay%5E%7B1%7D%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B3%5E3x%5E%7B2%2A3%7D%2Ay%5E%7B3%7D%2Ay%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B%5Cleft%283x%5E2y%5Cright%29%5E3%2Ay%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B%5Cleft%283x%5E2y%5Cright%29%5E3%7D%2A%5Csqrt%5B3%5D%7By%7D%5C%5C%5C%5C3x%5E2y%5Csqrt%5B3%5D%7By%7D%5C%5C%5C%5C)
Explanation:
As the steps above show, the goal is to factor the expression under the root in terms of pulling out cubed terms. That way when we apply the cube root to them, the exponents cancel. We cannot factor the y term completely, so we have a bit of leftovers.
