Answer:
Isosceles
Step-by-step explanation:
Consider triangle ABC, BD is the median and the altitude drawn to the side AC. This segment (BD) divide the triangle ABC into two triangles: ABD and CBD.
In these triangles:
- AD=DC (because BD is the median);
- ∠ADB=∠CDB=90° (because BD is the altitude);
- BD is common side.
Thus, by SAS postulate, triangles ABD and CBD are conruent. Congruent triangles have congruent corresponding sides. Hence, AB=CB.
If in triangle ABC, AB=BC, then this triangle is isosceles.
Answer:
<h2>x = 3 and y = 4</h2>
Step-by-step explanation:
We know:
The diagonals in a parallelogram divide by halves.
Therefore KG = UG and DG = CG.
We have
KG = 5y - 8, UG = 3y, DG = 4x - 7, CG = x + 2
Substitute:
5y - 8 = 3y <em>add 8 to both sides</em>
5y = 3y + 8 <em>subtract 3y from both sides</em>
2y = 8 <em>divide both sides by 2</em>
y = 4
---------------
4x - 7 = x + 2 <em>add 7 to both sides</em>
4x = x + 9 <em>subtract x from both sides</em>
3x = 9 <em>divide both sides by 3</em>
x = 3
Answer:
Carlos graphed the perpendicular bisector of the segment that joins the two points. (a line)
Step-by-step explanation:
Carlos graphed the set of points that are equidistant from both point A and point B.
Carlos graphed the perpendicular bisector of the segment that joins the two points. (a line)
