The solution to these equations is either x < 0 or x > 3.
In order to find them, we need to solve each equation separately. Let's start with the first one.
2x - 1 < -1 -----> Add 1 to both sides
2x < 0 -----> Now divide each side by 2.
x < 0
Now let's look at the second one.
-4x < -12 ----> Divide both sides by -4
x > 3 (Notice that the sign changes direction because we divided by a negative)
When you have an "or" statement, you'll wind up with two answers, so we use both of these.
The solution of the inequality is t<-3. Because -15 divided by 5t is equal to -3

notice where how many "yes" sign change happen in the positive "x"
and the on the negative "-x"
for the P(x) is 3 changes, thus
so is either 3 real positive ones, or 3-2 = 1 real positive one
P(-x) gives no sign changes, so there are 0 negative ones
the polynomial has a degree of 5, thus 5 roots
if it has 3 real positive ones, then it has 2 complex ones
the complex ones pick up the slack per se
if it has 1 real positive one, then it has 4 complex ones
bear in mind complex ones always come in pairs
It’s choice D since there are 6 0’s