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Svetllana [295]
3 years ago
5

The CEO of a clothing company estimates that 52% of customers will make a purchase. Part A: How many customers should a salesper

son expect until she finds a customer that makes a purchase? Part B: What is the probability that a salesperson helps 3 customers until she finds the first person to make a purchase?
Mathematics
1 answer:
4vir4ik [10]3 years ago
8 0

Answer:

(a) The expected number of should a salesperson expect until she finds a customer that makes a purchase is 0.9231.

(b) The probability that a salesperson helps 3 customers until she finds the first person to make a purchase is 0.058.

Step-by-step explanation:

Let<em> </em>the random variable <em>X</em> be defined as the number of customers the salesperson assists before a customer makes a purchase.

The probability that a customer makes a purchase is, <em>p</em> = 0.52.

The random variable <em>X</em> follows a Geometric distribution since it describes the distribution of the number of trials before the first success.

The probability mass function of <em>X</em> is:

P(X=x)=(1-p)^{x}p

The expected value of a Geometric distribution is:

E(X)=\frac{1-p}{p}

(a)

Compute the expected number of should a salesperson expect until she finds a customer that makes a purchase as follows:

E(X)=\frac{1-p}{p}

         =\frac{1-0.52}{0.52}\\=0.9231

This, the expected number of should a salesperson expect until she finds a customer that makes a purchase is 0.9231.

(b)

Compute the probability that a salesperson helps 3 customers until she finds the first person to make a purchase as follows:

P(X=3)=(1-0.52)^{3}\times0.52\\=0.110592\times 0.52\\=0.05750784\\\approx 0.058

Thus, the probability that a salesperson helps 3 customers until she finds the first person to make a purchase is 0.058.

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grin007 [14]

Answer:

x = -1 , y = -4 , z = -4

Step-by-step explanation:

Solve the following system:

{-x - 5 y + z = 17 | (equation 1)

-5 x - 5 y + 5 z = 5 | (equation 2)

2 x + 5 y - 3 z = -10 | (equation 3)

Swap equation 1 with equation 2:

{-(5 x) - 5 y + 5 z = 5 | (equation 1)

-x - 5 y + z = 17 | (equation 2)

2 x + 5 y - 3 z = -10 | (equation 3)

Subtract 1/5 × (equation 1) from equation 2:

{-(5 x) - 5 y + 5 z = 5 | (equation 1)

0 x - 4 y+0 z = 16 | (equation 2)

2 x + 5 y - 3 z = -10 | (equation 3)

Divide equation 1 by 5:

{-x - y + z = 1 | (equation 1)

0 x - 4 y+0 z = 16 | (equation 2)

2 x + 5 y - 3 z = -10 | (equation 3)

Divide equation 2 by 4:

{-x - y + z = 1 | (equation 1)

0 x - y+0 z = 4 | (equation 2)

2 x + 5 y - 3 z = -10 | (equation 3)

Add 2 × (equation 1) to equation 3:

{-x - y + z = 1 | (equation 1)

0 x - y+0 z = 4 | (equation 2)

0 x+3 y - z = -8 | (equation 3)

Swap equation 2 with equation 3:

{-x - y + z = 1 | (equation 1)

0 x+3 y - z = -8 | (equation 2)

0 x - y+0 z = 4 | (equation 3)

Add 1/3 × (equation 2) to equation 3:

{-x - y + z = 1 | (equation 1)

0 x+3 y - z = -8 | (equation 2)

0 x+0 y - z/3 = 4/3 | (equation 3)

Multiply equation 3 by 3:

{-x - y + z = 1 | (equation 1)

0 x+3 y - z = -8 | (equation 2)

0 x+0 y - z = 4 | (equation 3)

Multiply equation 3 by -1:

{-x - y + z = 1 | (equation 1)

0 x+3 y - z = -8 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Add equation 3 to equation 2:

{-x - y + z = 1 | (equation 1)

0 x+3 y+0 z = -12 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Divide equation 2 by 3:

{-x - y + z = 1 | (equation 1)

0 x+y+0 z = -4 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Add equation 2 to equation 1:

{-x + 0 y+z = -3 | (equation 1)

0 x+y+0 z = -4 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Subtract equation 3 from equation 1:

{-x+0 y+0 z = 1 | (equation 1)

0 x+y+0 z = -4 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Multiply equation 1 by -1:

{x+0 y+0 z = -1 | (equation 1)

0 x+y+0 z = -4 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Collect results:

Answer: {x = -1 , y = -4 , z = -4

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3 years ago
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

We use (BODMAS) :

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Division

Multiplication

Addition

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Now we do bracket first :

7(3²) = 7(9) = 63

Now we do division :

63÷3 = 21

Now we do multiplication :

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3 years ago
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