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emmasim [6.3K]
3 years ago
8

Let d represent the day of the month. Can d be 15? 56? 28? 0?

Mathematics
1 answer:
Mandarinka [93]3 years ago
7 0

Answer:

d can represent 15 and 28, but not 56 or 0.

Step-by-step explanation:

It can be October 15th or 28th, but not October 56th or October 0th

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Rewrite 25 and 125 as exponents that have the same base. Write your answers #^# and
dangina [55]

Answer:

  • 25 = 5^2
  • 125 = 5^3

Step-by-step explanation:

Both 25 and 125 are powers of 5. As such, they can be written as the powers they are:

  25 = 5·5 = 5^2

  125 = 25·5 = 5·5·5 = 5^3

3 0
3 years ago
I need help thanks in advance
sergij07 [2.7K]

Answer:

Step-by-step explanation:

The rule is if 2 chords intersect inside a circle, then the measure of the angle formed is one half the um of the measure of the arcs intercepted by the angle and its vertical angle. In other words, angle TSU = 1/2(arc TU + arc MV):

angle TSU = 1/2(90 + 80) and

angle TSU = 1/2(170) and

angle TSU = 85

6 0
3 years ago
Lamaj is rides his bike over a piece of gum and continues riding his bike at a constant rate time = 1.25 seconds the game is at
Hitman42 [59]

Lamaj rides his bike over a piece of gum and continues riding his bike at a constant rate. At time = 1.25 seconds, the gum is at a maximum height above the ground and 1 second later the gum is on the ground again.

a. If the diameter of the wheel is 68 cm, write an equation that models the height of the gum in centimeters above the ground at any time, t, in seconds.

b. What is the height of the gum when Lamaj gets to the end of the block at t = 15.6 seconds?

c. When are the first and second times the gum reaches a height of 12 cm?

Answer:

Step-by-step explanation:

a)

We are being told that:

Lamaj rides his bike over a piece of gum and continues riding his bike at a constant rate. This keeps the wheel of his bike in Simple Harmonic Motion and the Trigonometric equation  that models the height of the gum in centimeters above the ground at any time, t, in seconds.  can be written as:

\mathbf {y = 34cos (\pi (t-1.25))+34}

where;

y =  is the height of the gum at a given time (t) seconds

34 = amplitude of the motion

the amplitude of the motion was obtained by finding the middle between the highest and lowest point on the cosine graph.

\mathbf{ \pi} = the period of the graph

1.25 = maximum vertical height stretched by 1.25 m  to the horizontal

b) From the equation derived above;

if we replace t with 1.56 seconds ; we can determine the height of the gum when Lamaj gets to the end of the block .

So;

\mathbf {y = 34cos (\pi (15.6-1.25))+34}

\mathbf {y = 34cos (\pi (14.35))+34}

\mathbf {y = 34cos (45.08)+34}

\mathbf{y = 58.01}

Thus, the  gum is at 58.01 cm from the ground at  t = 15.6 seconds.

c)

When are the first and second times the gum reaches a height of 12 cm

This indicates the position of y; so y = 12 cm

From the same equation from (a); we have :

\mathbf {y = 34 cos(\pi (t-1.25))+34}

\mathbf{12 = 34 cos ( \pi(t-1.25))+34}

\dfrac {12-34}{34} = cos (\pi(t-1.25))

\dfrac {-22}{34} = cos(\pi(t-1.25))

2.27 = (\pi (t-1.25)

t = 2.72 seconds

Similarly, replacing cosine in the above equation with sine; we have:

\mathbf {y = 34 sin (\pi (t-1.25))+34}

\mathbf{12 = 34 sin ( \pi(t-1.25))+34}

\dfrac {12-34}{34} = sin (\pi(t-1.25))

\dfrac {-22}{34} = sin (\pi(t-1.25))

-0.703 = (\pi(t-1.25))

t = 2.527 seconds

Hence, the gum will reach 12 cm first at 2.527 sec and second time at 2.72 sec.

7 0
3 years ago
315% is what of 82.53
Aloiza [94]
315% is roughly 0.0382 of 82.53.
On the other hand, 315% of 82.53 is 259.9695 .
8 0
3 years ago
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A baby is weighed on a defective scale. He weighed 13 pounds. The baby weighs exactly 10 pounds. What is the percent error?
Eva8 [605]

Answer:

30%

Step-by-step explanation:

The answer is off by 30%, as the scale is off by 3 pounds. 3/10=30

4 0
3 years ago
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