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Bas_tet [7]
3 years ago
9

On a coordinate plane, a dashed straight line has a positive slope and goes through (negative 3, negative 7) and (0, 2). Everyth

ing to the left of the line is shaded. Which linear inequality is represented by the graph? y < 3x + 2 y > 3x + 2 y < One-thirdx + 2 y > One-thirdx + 2

Mathematics
2 answers:
Rzqust [24]3 years ago
8 0

Answer:

y>3x+2

Step-by-step explanation:

1) Find the slope, between (0,2) and (-3,-7) and then the linear parameter.

m=\frac{y_{2}-y_{1}}{x_{2}-x_{2}}\Rightarrow m=\frac{2+7}{0+3}\Rightarrow m=3\left \{ 2=0(3)+b \right.\Rightarrow b=2

2)Since it is a dashed line and the question says, everything to the left... then y > 3x+2. Rearranging it:

y=3x+2\Rightarrow y>3x-2

vagabundo [1.1K]3 years ago
6 0

Answer:

B)y > 3x +2

Step-by-step explanation:

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Help! Please! You can just give answers if want to make It faster.
sergiy2304 [10]

Answer:

X' = (-3 , -5)

Y' = (-1, -1)

Z' = (4, -8)

General rule: (x,y) = (y, -x)

I am 1 brainly away from the next rank, your help would be appreciated

8 0
3 years ago
If n + 10 = 45.5, then what is the value of the expression n - 25?
Citrus2011 [14]

Answer: 90

Step-by-step explanation:

45.5-.5=45

45^2=90

8 0
3 years ago
What's -3+(0+9) ?? <br> I need to know by tonight
Crank
The answer is 6.
To do this, remember PEMDAS? 
You would first have to add what is in the parenthesis THEN do -3 + 9 to get 6. 
6 0
3 years ago
Read 2 more answers
Suppose a batch of metal shafts produced in a manufacturing company have a standard deviation of 1.5 and a mean diameter of 205
Crank

Answer:

P(205-0.3=204.7

z=\frac{204.7-205}{\frac{1.5}{\sqrt{79}}}=-1.778

z=\frac{205.3-205}{\frac{1.5}{\sqrt{79}}}=1.778

So we can find this probability:

P(-1.778

And then since the interest is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.3 inches using the complement rule we got:

P = 1-0.9243 = 0.0757

Step-by-step explanation:

Let X the random variable that represent the diamters of interest for this case, and for this case we know the following info

Where \mu=205 and \sigma=1.5

We can begin finding this probability this probability

P(205-0.3=204.7

For this case they select a sample of n=79>30, so then we have enough evidence to use the central limit theorem and the distirbution for the sample mean can be approximated with:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{\bar x-\mu}{\frac{\sigma}{\sqrt{n}}}

And we can find the z scores for each limit and we got:

z=\frac{204.7-205}{\frac{1.5}{\sqrt{79}}}=-1.778

z=\frac{205.3-205}{\frac{1.5}{\sqrt{79}}}=1.778

So we can find this probability:

P(-1.778

And then since the interest is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.3 inches using the complement rule we got:

P = 1-0.9243 = 0.0757

6 0
3 years ago
Can you simplify 4/10
ryzh [129]
Yes! It can simplified to 2/5 or in decimal form it would be 0.4 . Hope this helps!
7 0
3 years ago
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