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horsena [70]
2 years ago
11

What is the inradius of a triangle with side lengths 9, 40, and 41?

Mathematics
1 answer:
Mars2501 [29]2 years ago
6 0

Answer: 20.5

Step-by-step explanation:

From the measure of the length of the sides of the triangle, 9, 40 and 41 we can infer that the triangle is a right angled triangle. 9-40-41 is a Pythagorean triplet.

In a right angled triangle, the circumradius is half the hypotenuse.

In the given triangle, the hypotenuse = 41.

Therefore, the circumradius is  41÷2= 20.5 units.

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Answer:

( x - 4)

Step-by-step explanation:

x² + 2x - 24

From here, you must find the two factors of -24 (the first and third terms' coefficients multiplied together) that add up to 2 (the middle terms coefficient)

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If 6 cost $60, how much do 8 cost​
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The length of the rectangular tennis court at wimbledon is 6 feet longer than twice the width. if the court's perimeter is 240 f
KATRIN_1 [288]

Length (L): 2w + 6

width (w): w

Perimeter (P) = 2L + 2w

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Answer: width = 38 ft, length = 82 ft

8 0
2 years ago
Triangle ABC has vertices A(-2,0), B(2,5), C(3, 1). The reflection of the image of triangle ABC is triangle A'B'C' with vertices
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Step-by-step explanation:

Given

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It is clear that the x coordinate remains unchanged and the y coordinate changes its sign. It occurs when reflection is done about the x-axis.

For example, when (a,b) is reflected about the x-axis, it becomes (a,-b).

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