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horsena [70]
3 years ago
11

What is the inradius of a triangle with side lengths 9, 40, and 41?

Mathematics
1 answer:
Mars2501 [29]3 years ago
6 0

Answer: 20.5

Step-by-step explanation:

From the measure of the length of the sides of the triangle, 9, 40 and 41 we can infer that the triangle is a right angled triangle. 9-40-41 is a Pythagorean triplet.

In a right angled triangle, the circumradius is half the hypotenuse.

In the given triangle, the hypotenuse = 41.

Therefore, the circumradius is  41÷2= 20.5 units.

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Answer:

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Step-by-step explanation:

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Read 2 more answers
Annie needs $30 to buy a coat she has saved $12 and plans to work as a baby siter to earn $6 per hour which inequality shows the
tekilochka [14]

Answer:

The answer would be B. 12 + 6n is greater than or equal to 30, so n is less than or equal to 3.

explanation:

I'm bad with explaining things, but I'll try my best to explain why this is the right answer.

12 + 6n ≥ 30, so n ≤ 3

let's start with the 12 at the beginning of the inequality, Annie already has $12, so the 12 in the inequality shows the amount of money she already has being added to the $6 per hour of babysitting she needs to do (n).

Now for the + 6n, the plus is there to show that the $12 Annie already has is being added to the 6n. The 6n then represents the $6 Annie makes each hour and the n represents how many hours she needs to babysit in order to get $30. The 6 is being multiplied by the amount of hours she needs to babysit to show how much money Annie would make. Then you add on the $12 she already has.

Annie then needs at least $30, but if she makes more than $30 then she will simply have more money than needed, therefore you use the greater than or equal to sign to show that she can have more money than just $30 after working.

I hope this helps, and sorry if my explanation is hard to understand lol.

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3 years ago
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