Answer:
depreciation to be allocated to A = 2800tons x $0.600 /ton
= $1680
Step-by-step explanation:
- First calculate the amount of depreciation/ton
- depreciation per ton = $125,000/208,000 = $0.600 /ton
- Hence depreciation to be allocated to A = 2800tons x $0.600 /ton
= $1680
The linear equations are y - 25 = 0.89(x - 20) and y = 0.89x + 7.2
<h3>The slope of the line</h3>
The complete question is added as an attachment
The two points from the graph are (20, 25) and (38, 41)
The slope of the line is calculated using
m = (y2 - y1)/(x2 - x1)
Substitute the known values in the above equation
m = (41 - 25)/(38 - 20)
Evaluate
m =0.89
<h3>The linear equation in point slope form</h3>
This is calculated as:
y - y1 = m(x - x1)
Substitute the known values in the above equation
y - 25 = 0.89 * (x - 20)
Evaluate
y - 25 = 0.89(x - 20)
<h3>The linear equation in slope-intercept form</h3>
We have:
y - 25 = 0.89(x - 20)
Expand
y - 25 = 0.89x - 17.8
Add 25 to both sides
y = 0.89x + 7.2
Hence, the linear equations are y - 25 = 0.89(x - 20) and y = 0.89x + 7.2
Read more about linear equations at:
brainly.com/question/4025726
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Answer:
15.1
Step-by-step explanation:
29.34
-14.24
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15.10
Answer:
twenty fifth
Step-by-step explanation: