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3 years ago

Solve log_x(1/32)=-5

1 answer:

3 0

Remember

$log_a(b)=c$ translates to $a^c=b$

so
$log_x(\frac{1}{32})=-5$ translates to $x^{-5}=\frac{1}{32}$
remember, if a^b=c^b when b=b, then a=c
and x^-m=1/(x^m)

hmm
$x^{-5}=\frac{1}{32}$
$\frac{1}{x^5}=\frac{1}{32}$
32=x⁵
5th root both sides
2=x
x=2

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3 years ago

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Ahat [919]

Answer:

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Any parabola is modelled by a second-order polynomial, whose standard form is:

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Where:

$x$ - Independent variable, dimensionless.

$y$ - Dependent variable, dimensionless.

$a$ , $b$ , $c$ - Coefficients, dimensionless.

In addition, a system of three linear equations is constructed by using all known inputs:

(-2, 0)

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$16\cdot a + 4\cdot b = 16$ (Eq. 5)

(Eq. 3 in Eqs. 1 - 2)

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$a = 4 + 0.5\cdot b$

Then,

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$a = 4 + 0.5\cdot b$

$a = 4 + 0.5\cdot (-4)$

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4 years ago

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