Answer:
40 ft × 75 ft
Step-by-step explanation:
Let x be the one side ( in feet ) of the rectangular parcel,
So, the diagonal between opposite corners = ( x + 10 ) feet,
Let y be the other side of the rectangle ( adjacent to side x ),
The area of the rectangle,
A = x × y,
According to the question,
A = 3000 square ft,
![\implies xy = 3000\implies y=\frac{3000}{x}](https://tex.z-dn.net/?f=%5Cimplies%20xy%20%3D%203000%5Cimplies%20y%3D%5Cfrac%7B3000%7D%7Bx%7D)
∵ In a rectangle,
![D^2=a^2+b^2](https://tex.z-dn.net/?f=D%5E2%3Da%5E2%2Bb%5E2)
Where, a and b are the adjacent side of the rectangle and D is the diagonal,
![(x+10)^2 = x^2 + y^2](https://tex.z-dn.net/?f=%28x%2B10%29%5E2%20%3D%20x%5E2%20%2B%20y%5E2)
![(x+10)^2 = x^2 + \frac{9000000}{x^2}](https://tex.z-dn.net/?f=%28x%2B10%29%5E2%20%3D%20x%5E2%20%2B%20%5Cfrac%7B9000000%7D%7Bx%5E2%7D)
![x^2(x+10)^2 = x^4 + 9000000](https://tex.z-dn.net/?f=x%5E2%28x%2B10%29%5E2%20%3D%20x%5E4%20%2B%209000000)
![x^2(x^2+100+20x) = x^4 + 9000000](https://tex.z-dn.net/?f=x%5E2%28x%5E2%2B100%2B20x%29%20%3D%20x%5E4%20%2B%209000000)
![x^4+100x^2 + 20x^3 = x^4 + 9000000](https://tex.z-dn.net/?f=x%5E4%2B100x%5E2%20%2B%2020x%5E3%20%3D%20x%5E4%20%2B%209000000)
![20x^3 + 100x^2 - 9000000=0](https://tex.z-dn.net/?f=20x%5E3%20%2B%20100x%5E2%20-%209000000%3D0)
![x^3 + 5x^2 - 450000 = 0](https://tex.z-dn.net/?f=x%5E3%20%2B%205x%5E2%20-%20450000%20%3D%200)
By graphing the equation,
We found that,
The only real zeros of the equation is at x = 75,
Hence, the one side of the rectangle = 75 ft,
And, second side =
= 40 ft
Hence, the dimension of the land is 40 ft × 75 ft