On the Sat the lowest value anyone can score on the math section is 200 and the highest is 800. Jason is a senior retaking the S
1 answer:
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Answer:
<em><u>hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>will help uh</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
We have been that frequency (y) varies inversely with wavelength (x).
We know that two inversely proportional quantities are in form , where a is inversely proportional to b and k is constant of variation.
Our required equation would be .
To find frequency of blue light, we will substitute and
in our equation as:
Therefore, the frequency of blue light is 764.
Answer:
Option D. The student did not use the correct formula to calculate the area of the segment
Step-by-step explanation:
step 1
Find the area of the isosceles triangle
Applying the law of sines
step 2
Find the area of the sector
The area of the sector is 1/6 of the area of the circle
so
substitute the value
step 3
Find the area of the segment
The area of the segment is equal to the area of sector minus the area of triangle
therefore
The student did not use the correct formula to calculate the area of the segment