Answer:
The equation of the line is 2 x - y + 5 = 0.
Step-by-step explanation:
Here the given points are A( 1, 7) & B( -3, - 1) -
Equation of a line whose points are given such that
(
) & (
)-
y -
=
( x -
)
i.e. <em> y - 7=
( x- 1)</em>
<em> y - 7 =
( x -1)</em>
<em> y - 7 = 2 ( x - 1) </em>
<em> y - 7 = 2 x - 2</em>
<em> 2 x - y + 5 = 0</em>
Hence the equation of the required line whose passes trough the points ( 1, 7) & ( -3, -1) is 2 x - y + 5 = 0.
The algebraic expression you would write is 12v
Angles of a triangle = 180 degrees
T + C = 110 degrees, and T=C (according to the definition of an isosceles triangle).
measure of T is 110/2 which equals 55 degrees
Well (1.57- 0.6 X 0.6) x 0.3 = 0.363
Answer:
use distance formula for the sides of the triangle