Ya, calculus and related rates, such fun!
everything is changing with respect to t
altitude rate will be dh/dt and that is 1cm/min
dh/dt=1cm/min
area will be da/dt which is increasing at 2cm²/min
da/dt=2cm²/min
base=db/dt
alright
area=1/2bh
take dervitivie of both sides
da/dt=1/2((db/dt)(h)+(dh/dt)(b))
solve for db/dt
distribute
da/dt=1/2(db/dt)(h)+1/2(dh/dt)(b)
move
da/dt-1/2(dh/dt)(b)=1/2(db/dt)(h)
times 2 both sides
2da/dt-(dh/dt)(b)=(db/dt)(h)
divide by h
(2da/dt-(dh/dt)(b))/h=db/dt
ok
we know
height=10
area=100
so
a=1/2bh
100=1/2b10
100=5b
20=b
so
h=10
b=20
da/dt=2cm²/min
dh/dt=1cm/min
therefor
(2(2cm²/min)-(1cm/min)(20cm))/10cm=db/dt
(4cm²/min-20cm²/min)/10cm=db/dt
(-16cm²/min)/10cm=db/dt
-1.6cm/min=db/dt
the base is decreasing at 1.6cm/min
Answer:
-3 X 7= -21
Step-by-step explanation:
Answer:
Step-by-step explanation:
The answer is 1.3
Find area of room
aera=legnth wtimes width
in a square, legnth=width
aera=legnth^2
legnth=14 feet
convert o inches
14*12=168 inches
area=168^2=28224 square inches
how many tiles will cover all of floor?
aka
how many 192 in^2 is at least 28224 (at least, because we need to cover the whole floor without gaps)
192x<u>></u>28224
divide both sides by 192
x<u>></u>147
147 is the number of tiles we need
Given that the half life of 3H is 12.3 years.
The amount of substance left of a radioactive substance with half life of
after t years is given by
Therefore, the number of years it will take for 18% of the original tritinum to remain is given by
Therefore, the number of <span>years that the time could be read at night is 30.4 years.</span>
