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4 years ago

Is this correct???? TYSM

Mathematics

1 answer:

vfiekz [6]4 years ago

5 0

Yep, this is all correct!

-6/2 = y/4

y = (-6×4)/2

y = -24/2

y = -12

x was multiplied by 2

and y was also multiplied by 2

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Ms. Johnson asked her class to write an equivalent expression to

dimulka [17.4K]

No one got the correct answer. The answer is supposed to be 7(2d+3k-dk-1). All the coefficients are divisible by 7, thus only the integers are changed. However, the variables cannot be a factor because they do not have the same variables that all the coefficients must have.

7 0

3 years ago

Help please, asap, And take your time answering please!

ankoles [38]

Answer:

(a) 25

(b) (5+4)*2 +6 -2*2 -1

Step-by-step explanation:

(a) evaluating exponents:

6*7 -9*9 +64

Evaluating products:

42 -81 +64

Evaluating sums:

-39 +64

(b) The last three terms of the expression sum to +1, and it is fairly easy to modify the first two terms to make one term that has a value of 18. Then the expression evaluates as 18+1 = 19.

(5+4)*2 +6 -2*2 -1

(c) Evaluating parentheses:

= 9*2 +6 -2*2 -1

Evaluating products:

= 18 +6 -4 -1

Evaluating sums (left to right):

= 24 -4 -1

= 20 -1

= 19

5 0

3 years ago

Tell if each equation represents exponential growth, exponential decay or neither.

scoray [572]

Answer:

Exponential growth A, B;

exponential decay C, E;

neither D.

Step-by-step explanation:

The function $y=a\cdot b^x$

represents exponential growth when $b>1;$
represents exponential decay when $0$

A. The equation $f(t)=\dfrac{2}{3}\cdot \left(\dfrac{7}{3}\right)^t$ represents exponential growth, because $\dfrac{7}{3}>1.$

B. The equation $P=22\cdot \left(1.76\right)^x$ represents exponential growth, because $1.76>1.$

C. The equation $V=\dfrac{1}{3}\cdot \left(0.45\right)^x$ represents exponential decay, because $0$

D. The equation $W=3.2\cdot (x)$ represents neither exponential growth nor exponential decay, because this function is linear.

E. The equation $g(x)=4.2\cdot \left(\dfrac{1}{3}\right)^x$ represents exponential decay, because $0$

3 0

4 years ago

A group of engineers developed a new design for a steel cable. They need to estimate the amount of weight the cable can hold. Th

igor_vitrenko [27]

Answer:

The 95% confidence interval for the mean breaking weight for this type cable is (767.47 lb, 777.13 lb).

Step-by-step explanation:

Our sample size is 41

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 41-1 = 40$

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 40 and 0.025 in the two-sided t-distribution table, we have $T = 2.021$

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{15.3}{\sqrt{41}} = 2.39$

Now, we multiply T and s

$M = T*s =2.021*2.39 = 4.83$

Then

The lower end of the confidence interval is the mean subtracted by M. So:

$L = 772.3 - 4.83 = 767.47$

The upper end of the confidence interval is the mean added to M. So:

$L = 772.3 + 4.83 = 777.13$

The 95% confidence interval for the mean breaking weight for this type cable is (767.47 lb, 777.13 lb).

5 0

3 years ago

Choose the correct answer

vivado [14]

This is actually called a mapping diagram but the answer is C.

Because the right circle represents the x variable and the left circle is the y variable. So you just follow the arrows. -3 is pointing to 4 so that's a pair or (-3,4)

8 0

4 years ago