Apply distributive property
(5x+6)-(2x-3)
=5x+6-2x+3 arrange like terms
Simplify =5x-2x+6+3
Equals 3x+9 final answer
Complete question :
A right triangle has side lengths AC = 7 inches, BC = 24 inches, and AB = 25 inches.
What are the measures of the angles in triangle ABC?
a) m∠A ≈ 46.2°, m∠B ≈ 43.8°, m∠C ≈ 90°
b) m∠A ≈ 73.0°, m∠B ≈ 17.0°, m∠C ≈ 90°
c) m∠A ≈ 73.7°, m∠B ≈ 16.3°, m∠C ≈ 90°
d) m∠A ≈ 74.4°, m∠B ≈ 15.6°, m∠C ≈ 90°
Answer:
c) m∠A ≈ 73.7°, m∠B ≈ 16.3°, m∠C ≈ 90°
Step-by-step explanation:
Given:
Length AC = 7 inches
Length BC = 24 inches
Length AB = 25 inches
Since it is a right angle triangle,
m∠C = 90°
To find the measures of the angle in ∠A and ∠B, we have :
For ∠A:
∠A = 73.7°
For ∠B:
∠B = 16.26 ≈ 16.3°
Therefore,
m∠A = 73.7°
m∠B = 16.3°
m∠C = 90°
80 inches or feet.. I think you are suppose to multiply 40x2 sorry if im wrong
Answer: -7twice
Step-by-step explanation:
This is a question on root of quadratic equation. The interpretation of the question
x² 14x + 49 is
x² + 14x + 49 = 0.meaning that we are to find two possible values for x that will make the expression equal 0.
We can use any of the methods earlier taught. For the purpose of this class, I am using factorization methods
x² + 14x + 49 = 0
Now, find the product of the first and the last terms, is
x² × 49 = 49ײ
Now find two terms such that their productbis 49x² and their sum equals 14x, the one in the middle.
We have several factors of 49x² but only one will give sum of 14x. Because of the time, I will only go straight to the required factors .
49x² = 7x × 7x and the sum gives 14x the middle terms..
Now we now replace the middle one by the factors and then factorize by grouping.
x² + 14x + 49 = 0
x² + 7x + 7x + 49 = 0
x(x + 7) + 7(x + 7) = 0
(x + 7)(x + 7). = 0
Now to find this value of x,
x + 7 = 0
x. = -7twice.
The root of the equation = -7twice.
Answer:
1- they are proportional
2- that one is right
Step-by-step explanation:
k so
x and y are proportional bcuz y will always be 1/3 of x, and if u drew a line on the graph it would go thru the origin
