Answer:
The GFCI shuts down the circuit when it senses a current leakage.
Explanation:
The ground of a circuit should truly be ground. But if the ground circuit is not truly ground, then someone could get shocked. The GFCI monitors the possibility of current flow to ground. If this occurs, then the GFCI stops all flow of current, for safety reasons.
It also monitors if the current flow is interrupted. Say you drop something that is plugged in, into a sink of water. The GFCI should note the current loss, and shut down the circuit.
GFCI stands for: Ground-Fault Circuit Interrupter
Answer:
1. G=D+(A+C^2)*E/(D+B)^3
cobegin:
p1: (D+B)
p2: p1^3
p3: C^2
p4: A+ p3
p5: E/p2
p6: p4 * p5
p7: D + p6
:G
coend
2. Now The value A=2, B=4, C=5, D=6, and E=8
p1: 6+4 =10
p2: p1 ^3= 10^3= 1000
p3: c^2= 5^2 =25
p4: A + p3= 2 +25 =27
p5: 8/1000
p6: 27 *8/1000
p7: D+ P6= 6+ 216/1000
= 6216/1000
=6.216
Explanation:
The above, first bracket with power is processed, and then power inside and outside bracket. And rest is according to BODMAS, and one process is solved at a time.
Answer:
Algorithm:
1. Declare and initialize variable one_dog_year=7.
2.Ask user to give dog age.
2.1 Read the dog age and assign it to variable "dog_age".
3.Create a variable "human_age" to store the equivalent human age.
3.1 Calculate equivalent human age as "human_age=one_dog_year*dog_age".
4.Print the equivalent human age of dog age.
7. End the program.
// here is algorithm implemented in c++
#include <bits/stdc++.h>
using namespace std;
int main()
{
// initialize one dog year
int one_dog_year=7;
int dog_age;
int equi_h_age;
cout<<"Enter the dog age:";
// read the dog age
cin>>dog_age;
//calculate the equivalent human age
equi_h_age=dog_age*one_dog_year;
cout<<"equivalent human age is : "<<equi_h_age<<endl;
return 0;
}
Output:
Enter the dog age:2
equivalent human age is : 14
Answer:
B.O(n).
Explanation:
In an ADT graph the method addEdge uses an Array of list.So in the worst case and the worst will be when the list already has n elements in it.
So to add an edge we have to iterate over the list upto nth element and then add the edge after that.So it has to travel over n elements.
So we can say that the answer is O(n).
Answer:
Receiver
Explanation:
bcz the private key is kept only by the receiver of the message.
