Answer:
Explanation:
The following is written in Java. It creates the function num_eights and uses recursion to check how many times the digit 8 appears in the number passed as an argument. A test case has been created in the main method and the output can be seen in the image below highlighted in red.
public static int num_eights(int pos){
if (pos == 0)
return 0;
if (pos % 10 == 8)
return 1 + num_eights(pos / 10);
else
return num_eights(pos / 10);
}
Answer:
The answer to this question is given below in the explanation section.
Explanation:
First, we need to convert these hexadecimal numbers into decimal numbers, then we can easily identify which one is the lowest hexadecimal.
The hexadecimal numbers are F2, 81, 3C, and 39.
F2 = (F2)₁₆ = (15 × 16¹) + (2 × 16⁰) = (242)₁₀
81 = (81)₁₆ = (8 × 16¹) + (1 × 16⁰) = (129)₁₀
3C = (3C)₁₆ = (3 × 16¹) + (12 × 16⁰) = (60)₁₀
39 = (39)₁₆ = (3 × 16¹) + (9 × 16⁰) = (57)₁₀
The 39 is the lowest hexadecimal number among the given numbers.
Because 39 hex is equal to 57 decimal.
39 = (39)₁₆ = (3 × 16¹) + (9 × 16⁰) = (57)₁₀
B. hand gestures
these are not verbal.
Answer:
because if you throttle it then
you can make sure it's okay
Answer:
From a hardware standpoint, the CPU is most likely the main component. From a software standpoint, macOS and Windows are complex software systems.
Explanation:
