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Tatiana [17]
3 years ago
8

Are integers irrational

Mathematics
2 answers:
MAXImum [283]3 years ago
8 0
Integers<span> can be expressed as a fraction. Example 5=5/</span><span>1. so not all integers are irrational.</span>
AVprozaik [17]3 years ago
3 0
Well, some integers can be irrational, but not all! :) 
You might be interested in
Find m/KMN. L 60° K 1⁰40 6x (11x+15)° N​
miskamm [114]

Answer:

  114°

Step-by-step explanation:

The exterior angle is the sum of the remote interior angles.

__

<h3>setup</h3>

  (11x +15)° = 60° +6x°

<h3>solution</h3>

  5x = 45 . . . . . . . . . divide by °, subtract 15+6x

  x = 9 . . . . . . . . . . divide by 5

The measure of exterior angle KMN is ...

  m∠KMN = (11(9) +15)° = 114°

_____

<em>Additional comment</em>

Both the sum of interior angles and the sum of angles of a linear pair are 180°. If M represents the interior angle at vertex M, then we have ...

  60° +6x° +M = 180°

  (11x +15)° +M = 180°

Equating these expressions for 180° and subtracting M gives the relation we used above:

  (11x +15)° +M = 60° +6x° +M . . . . . equate the two expressions for 180°

  (11x +15)° = 60° +6x° . . . . . . . . . . . subtract M

This is also described by "supplements to the same angle are equal."

4 0
2 years ago
Read 2 more answers
11. What is the vertex of ZLMN?
astraxan [27]
ANSWER: (5,2)

according to the graph, the vertices of the
curve are 5 in abscissa and 2 in ordinate
hence the vertex (5,2)
3 0
2 years ago
Why do people keep adding links instead of answering my? question
Svet_ta [14]

I know! It's kind if annoying tbh...

7 0
3 years ago
Find de product of 15 and 107
Andru [333]

Answer:

15 \times 107 = 1605

6 0
3 years ago
Read 2 more answers
Define the double factorial of n, denoted n!!, as follows:n!!={1⋅3⋅5⋅⋅⋅⋅(n−2)⋅n} if n is odd{2⋅4⋅6⋅⋅⋅⋅(n−2)⋅n} if n is evenand (
tekilochka [14]

Answer:

Radius of convergence of power series is \lim_{n \to \infty}\frac{a_{n}}{a_{n+1}}=\frac{1}{108}

Step-by-step explanation:

Given that:

n!! = 1⋅3⋅5⋅⋅⋅⋅(n−2)⋅n        n is odd

n!! = 2⋅4⋅6⋅⋅⋅⋅(n−2)⋅n       n is even

(-1)!! = 0!! = 1

We have to find the radius of convergence of power series:

\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{2^{n}[(n+9)!]^{3}(4n+3)!!}](8x+6)^{n}\\\\\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{2^{n}[(n+9)!]^{3}(4n+3)!!}]2^{n}(4x+3)^{n}\\\\\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{[(n+9)!]^{3}(4n+3)!!}](x+\frac{3}{4})^{n}\\

Power series centered at x = a is:

\sum_{n=1}^{\infty}c_{n}(x-a)^{n}

\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{2^{n}[(n+9)!]^{3}(4n+3)!!}](8x+6)^{n}\\\\\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{2^{n}[(n+9)!]^{3}(4n+3)!!}]2^{n}(4x+3)^{n}\\\\\sum_{n=1}^{\infty}[\frac{8^{n}4^{n}n!(3n+3)!(2n)!!}{[(n+9)!]^{3}(4n+3)!!}](x+\frac{3}{4})^{n}\\

a_{n}=[\frac{8^{n}4^{n}n!(3n+3)!(2n)!!}{[(n+9)!]^{3}(4n+3)!!}]\\\\a_{n+1}=[\frac{8^{n+1}4^{n+1}n!(3(n+1)+3)!(2(n+1))!!}{[(n+1+9)!]^{3}(4(n+1)+3)!!}]\\\\a_{n+1}=[\frac{8^{n+1}4^{n+1}(n+1)!(3n+6)!(2n+2)!!}{[(n+10)!]^{3}(4n+7)!!}]

Applying the ratio test:

\frac{a_{n}}{a_{n+1}}=\frac{[\frac{32^{n}n!(3n+3)!(2n)!!}{[(n+9)!]^{3}(4n+3)!!}]}{[\frac{32^{n+1}(n+1)!(3n+6)!(2n+2)!!}{[(n+10)!]^{3}(4n+7)!!}]}

\frac{a_{n}}{a_{n+1}}=\frac{(n+10)^{3}(4n+7)(4n+5)}{32(n+1)(3n+4)(3n+5)(3n+6)+(2n+2)}

Applying n → ∞

\lim_{n \to \infty}\frac{a_{n}}{a_{n+1}}= \lim_{n \to \infty}\frac{(n+10)^{3}(4n+7)(4n+5)}{32(n+1)(3n+4)(3n+5)(3n+6)+(2n+2)}

The numerator as well denominator of \frac{a_{n}}{a_{n+1}} are polynomials of fifth degree with leading coefficients:

(1^{3})(4)(4)=16\\(32)(1)(3)(3)(3)(2)=1728\\ \lim_{n \to \infty}\frac{a_{n}}{a_{n+1}}=\frac{16}{1728}=\frac{1}{108}

4 0
3 years ago
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