How did you compute sums of dollar amounts that were not whole numbers? For example, how did you compute the sum of$5.89 and$1.4
5? Use this example to explain your strategy. 2.
2 answers:
Answer:
$7.34
Step-by-step explanation:
To compute sum of dollars that are not whole numbers. Using the sum of$5.89 and$1.45 as an illustration :
$5.89 + $1.45
Taking the whole numbers first:
$5 + $1 = $6
Take the sum of the decimals :
$0.89 + $0.45 = $1.34
Sum initial whole + whole of sum of decimal
$6 + $1 = $7
Remaining decimal : $1.34 - $1 = $0.34
$7 + $0.34 = $7.34
Answer:
$7.34
Step-by-step explanation:
To compute sum of dollars that are not whole numbers. Using the sum of$5.89 and$1.45 as an illustration :
$5.89 + $1.45
Taking the whole numbers first:
$5 + $1 = $6
Take the sum of the decimals :
$0.89 + $0.45 = $1.34
Sum initial whole + whole of sum of decimal
$6 + $1 = $7
Remaining decimal : $1.34 - $1 = $0.34
$7 + $0.34 = $7.34
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2- 3x + 20 = 35
I think the answer is A. Cause your supposed to subtract so 7n-4n=3n, and 3-2=1 :) I hope this helps
Answer:
B. (x-3)^2
Step-by-step explanation:
x^2-6x+9 = (x-3)^2
(a-b)^2=a^2-2ab+b^2
(a+b)^2=a^2+2ab+b ^2
X=1
3+4=7
3x1=3
3+4 =6 so X =1
