3 out of 5 picks are orange. if 12 picks are orange haw many picks are in all
2 answers:
In this problem we'll work with fractions and equality:
So, "3 out of 5" is represented by . The numerator is the number of orange picks, and the denominator is the total number of picks.
So, if we have 12 orange picks, it means that from our original fraction () the 3 became a 12, which means it has been multiplied by 4. Finally, we multiply our denominator by the same number: 4 * 5 = 20
Therefore:
In all, there were 20 picks, 12 of them orange, or as a fraction,
Hope it helped,
BioTeacher101
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Answer:
a) The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.
b) The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.
Step-by-step explanation:
Question a:
We have to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Z-table as such z has a p-value of .
That is z with a p-value of , so Z = 1.96.
Now, find the margin of error M as such
In which is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 45420 - 574 = $44,846.
The upper end of the interval is the sample mean added to M. So it is 45420 + 574 = $45,994.
The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.
Question b:
The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.