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REY [17]
3 years ago
7

3 out of 5 picks are orange. if 12 picks are orange haw many picks are in all

Mathematics
2 answers:
xxTIMURxx [149]3 years ago
7 0

Answer:

There were 20 picks total

Step-by-step explanation:

We can use a proportion to solve this problem.  Put the orange picks on top and the total picks on bottom

3 orange         12 orange

-------------- =   ---------------

5 total                x total

Using cross products

3x = 5*12

3x= 60

Divide each side by 3

3x/3 = 60/3

x = 20

There were 20 picks total

BlackZzzverrR [31]3 years ago
6 0

In this problem we'll work with fractions and equality:

So, "3 out of 5" is represented by \frac{3}{5}. The numerator is the number of orange picks, and the denominator is the total number of picks.

So, if we have 12 orange picks, it means that from our original fraction (\frac{3}{5}) the 3 became a 12, which means it has been multiplied by 4. Finally, we multiply our denominator by the same number: 4 * 5 = 20


Therefore:

In all, there were 20 picks, 12 of them orange, or as a fraction, \frac{12}{20}



Hope it helped,



BioTeacher101

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Morgarella [4.7K]

Answer:

=5x+1          or          =5x-1

Step-by-step explanation:

One is given the following equation:

5x-\frac{\sqrt{9x^2-6x+1}}{1-3x}

The problem asks one to simplify the expression, the first step in solving this equation is to factor the equation.  Rewrite the numerator and denominator of the fraction as the product of two expressions. Remember the factoring patterns:

(a-b)^2=a^2-2ab+b^2

=5x-\frac{\sqrt{9x^2-6x+1}}{1-3x}

=5x-\frac{\sqrt{(3x-1)^2}}{-(3x-1)}

Now simplify the numerator. Remember, taking the square root of a squared value is the same as taking the absolute value of the expression,

=5x-\frac{\sqrt{(3x-1)^2}}{1-3x}

=5x-\frac{|3x-1|}{-(3x-1)}

Rewrite the expression without the absolute value sign in the numerator. Remember the general rule for removing the absolute value sign:

|a-b|\\=a -b           or           (-a-b) = b-a

=5x-\frac{|3x-1|}{-(3x-1)}

=5x-\frac{3x-1}{-(3x-1)}          or          =5x-\frac{-(3x-1)}{-(3x-1)}

Simplify both expressions, reduce by canceling out common terms in both the numerator and the denominator,

=5x-\frac{3x-1}{-(3x-1)}          or          =5x-\frac{-(3x-1)}{-(3x-1)}

=5x-(-1)          or          =5x-(1)

Simplify further by rewriting the expression without the parenthesis, remember to distribute the sign outside the parenthesis by the terms inside of the parenthesis; note that negative times negative equals positive.

=5x-(-1)          or          =5x-(1)

=5x+1          or          =5x-1

6 0
3 years ago
Finding Domain.
Katarina [22]
(f \circ g)(x)=(\sqrt{x-5})^2+2=x-5+2=x-3\\&#10;D:x\in \mathbb{R}
6 0
3 years ago
PLEASE HEWP :") THE STRUGGLE IS REAL MY G
andre [41]

Answer:

i think so 3/4 If i am wrong plz anyone say the correct answer

8 0
3 years ago
Subtract.<br><br> 7 1/5 − (−3/5)
mojhsa [17]

This would just be 7 1/5 + 3/5 since the negative sign gets distributed and makes (-3/5) into a positive number.

From there you have basic math and you get 7 4/5.

5 0
3 years ago
Read 2 more answers
Help please I forgot my notes<br>Need answers asap- it's due in a few hours<br>​
ahrayia [7]

I'm not to sure if I know the other ones but number 12th Is 6

Step-by-step explanation:

Since the two lines intersect at point Q(x,y) the x & y values of both lines must be equal at point Q. so 3x+14=7x-10. Solving for x yields x = 6.

4 0
3 years ago
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