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JulijaS [17]
3 years ago
12

Which relation defines y as a function of x?

Mathematics
1 answer:
UkoKoshka [18]3 years ago
8 0

Answer:

A function is a relation in which each input has only one output. In the relation, y is a function of x, because for each input x (1, 2, 3, or 0), there is only one output y.

Step-by-step explanation:

For every x there is exactly one y value. We can forgive a function if some values of x do not have a y, but if there is more than one y for even one value of x, then the relation is not a function.

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$1500 divided by 12 months = $125 per month. 0.75% x 120 (10 years x 12 months in each) = 90%. $125 x 120 = $15,000 + ($125 x 90%= $11,250) = $26,250. $26,250 + $2500 = $28,750 overall in the account after 10 years
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Find the surface area and please explain​
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Step-by-step explanation:

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3 years ago
The binomial 5x – 4 is a factor of 10x2 – 23x + 12. What is the other factor?
SVETLANKA909090 [29]
Method\ 1^o\\10x^2-23x+12=(5x-4)(ax+b)\\\\10x^2-23x+12=5ax^2+5bx-4ax-4b\\\\10x^2-23x+12=5ax^2+(5b-4a)x-4b\\\\therefore\\\\  \begin{array}{ccc}(1)\\(2)\\(3)\end{array}\left\{\begin{array}{ccc}5a=10\\5b-4a=-23\\-4b=12\end{array}\right\\\\(1)\ divide\ both\ sides\ by\ 5\to a=2\\(3)\ divide\ both\ sides\ by\ (-4)\to b=-3\\check\\subtitute\ the\ values\ of\ "a"\ and\ "b"\ to\ (2):\\5\cdot(-3)-4\cdot2=-15-8=-23\ /correct/\\\\Answer:\boxed{2x-3}


Method\ 2^o\\10x^2-23x+12=10x^2-8x-15x+12\\=2x\cdot5x-2x\cdot4-3\cdot5x-3\cdot(-4)\\=2x(5x-4)-3(5x-4)=(5x-4)\boxed{(2x-3)}
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3 years ago
A rectangle has an area of 82 ft2. What is<br> the length if the width is 10 ft?
Luda [366]

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Step-by-step explanation:

7 0
3 years ago
AD is a diameter of a circle and AB is a chord. If AD=34cm, AB=30cm, the distance of AB from the centre of the circle is :
e-lub [12.9K]

Answer:

   The distance is 8 cm

Step-by-step explanation:

The chord and the diameter form one leg and the hypotenuse of a right triangle. The other leg, BD, has length ...

  BD² +AB² = AD²

  BD² = AD² -AB² = 34² -30² = 256

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The segment from the center of the circle to the midpoint of the chord is the midline of triangle ABD, so is half the length of BD.

  distance from AB to the center = 16/2 = 8 . . . cm

7 0
3 years ago
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