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4vir4ik [10]
3 years ago
14

How to solve in long division 82.14 divided by 6.

Mathematics
1 answer:
omeli [17]3 years ago
7 0

Answer: 13.69

Step-by-step explanation:

82.14/6=

Multiply 82.14 by 100 to make it a whole number; since you're modifying the number, you must also multiply 6 by 100 in order to keep it balanced.

82.14*100/6*100

8214/600

---------------------------------------------------------------------

Let's begin.

8214/600=13.69

600

----------

221'4

1800

--------

414'0

3600

--------------

540'0

5400

-----------

    -

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I need help solving this problem |5x - 1| < 1
VashaNatasha [74]

Imagine what the graph would look like. Does it open upwards or downwards?

5x - 1 has a positive slope of 5 and it is reflected horizontally. The graph would be shaped like a V. A limited segment, or none, of the graph is below a certain value of y, and the rest outside it is above.

Hence, the solution must be a < x < b.

|5x - 1| < 1

5x - 1 < 1

x < 2/5

|5x - 1| < 1

5x - 1 > -1

x > 0

0 < x < 2/5

4 0
3 years ago
In the real numbers what is the solution of the equation 8^2x+1=4^1-x
Anna11 [10]
3/65
is the awnser.good day


3 0
3 years ago
The graphs below have the same shape. What is the equation of the blue
d1i1m1o1n [39]

Answer:

C

Step-by-step explanation:

4 0
3 years ago
The sum of two integers is 81.if the product is 1088.what are the integers
arlik [135]

Answer:

(a;b)={(17; 64); (64; 17)}

Step-by-step explanation:

a+b=81 => b=81-a

a*b=1088

a*(81-a)=1088

-a²+81a=1088

a²-81a+1088=0

a²-64a-17a+1088=0

a(a-64)-17(a-64)=0

(a-17)(a-64)=0

=> a=17 and a=64

for a=17 => b=81-17=64

for a=64 => b=81-64=17

(a;b)={(17; 64); (64; 17)}

3 0
3 years ago
mark invests 8000 in an account that pays 12% interest and 2000 in one that pays 8%. if he leaves the money in the accounts for
frez [133]

mark must leave it for 5.5 months or 5 and half moths to gain 5600 in interest​ .

<u>Step-by-step explanation:</u>

Here we have , mark invests 8000 in an account that pays 12% interest and 2000 in one that pays 8%. if he leaves the money in the accounts for the same length of time, We need to find how long must he leave it to gain 5600 in interest​ . Let's find out:

Let mark invests 8000 in an account that pays 12% interest and 2000 in one that pays 8% for time x months , So total interest gain is 5600 i.e.

⇒ \frac{8000(12)}{100}(x) +\frac{2000(8)}{100}(x) =5600

⇒ \frac{8000(12)+2000(8)}{100}(x) =5600

⇒ (80(12)+20(8))(x) =5600

⇒ (960+160)(x) =5600

⇒ (1020)(x) =5600

⇒ x =\frac{5600}{1020}

⇒ x =5.5

Therefore , mark must leave it for 5.5 months or 5 and half moths to gain 5600 in interest​ .

6 0
3 years ago
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