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KengaRu [80]
2 years ago
10

If a worker can do his job in 5 hours, and a student can do the same job in 8 hours, what part of the work is left to finish aft

er two hours of work? NOTE: THEY WORKED TOGETHER
ANSWER: FRACTIOn
Mathematics
2 answers:
Aleks [24]2 years ago
8 0

Answer:

Part of work left to finish after two work hours is 7/20

Step-by-step explanation:

Firstly, we need to calculate their joint work rate

That will be;

1/(1/5 + 1/8) = 1/(13/40) = 40/13

This means that they will complete the task in 40/13 hours

1 whole part takes 40/13

x part will take 2 hours

x * 40/13 = 2

40x = 26

x = 26/40

So the part that will be completed in two hours is 26/40

This means that the part left to complete will be:

1 - 26/40 = 14/40 = 7/20

Mrac [35]2 years ago
8 0

Answer:

7/20

Step-by-step explanation:

you need to find what is left, not how much they did (which is 13/20)

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Hatshy [7]
<span>y - 2418.6 = 5.9(x - 54)
y - 2418.6 = 5.9x - 318.6
y = 5.9x + 2100 
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Now we can answer:
What is the weight of the plane with 26 gallons of fuel in its tank? 
f(26) = 5.9(26) + 2100 = 2253.4 pounds 
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3 0
3 years ago
Which is the correct expansion of (3x + 2y)5?
Kisachek [45]

Answer:

15x +10y

Step-by-step explanation:

Just multiply 5x and 2y times 5 and don't combine them since they are different terms.

5 0
2 years ago
A right cylinder has a radius of 6 m and a surface area of 84 m². Find the surface area of a similar cylinder with a radius of 2
dlinn [17]

Answer:

The surface area of the second cylinder is equal to 9.33\ m^{2}

Step-by-step explanation:

we know that

If two figures are similar then

the ratio of their surfaces areas is equal to the scale factor squared

Let

z-------> the scale factor

x------> the surface area of the smaller cylinder (second cylinder)

y-------> the surface area of the original cylinder (first cylinder)

so

z^{2}=\frac{x}{y}

Step 1

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z=\frac{2}{6}=\frac{1}{3}

Step 2

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we have

z=\frac{1}{3}

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substitute and solve for x

(\frac{1}{3})^{2}=\frac{x}{84}

x=\frac{1}{9}*84=9.33\ m^{2}


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2 years ago
Help plz!!!!!!!!!!!!!!!!!!!!!!!!!!!!
blondinia [14]
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