You just want to simplify right?!
45. (a^2b^3)(ab)^-2
= (a^2b^3)(a^-2b^-2)
= b
46. (-3x^3y)^2(4xy^2)
= (-9x^6y^2)(4xy^2)
= -36x^7y^4
47. 3c^2d(2c^3d^5) / 15c^4d^2
= 6c^5d^6 / 15c^4d^2
= 2/5c1/4x^4
48. -10g^6h^9(g^2h^3) / 30g^3h^3
= -10g^8h^12 / 30g^3h^3
= -1/3g^5h^9
49. 5x^4y^2(2x^5y^6) / 20x^3y^5
= 10x^9y^8 / 20x^3y^5
= 1/2x^6 1/3y^3
50. -12n^7p^5(n^2p^4) / 36n^6p^7
= -12n^9p^9 / 36n^6p^7
= -1/3n^3p^2
(Sorry it’s messy it’d look better if my phone could actually put the numbers to the power)
Answer:
60
The angle acute so my guess is 60
Hope this helps :)
Answer:
10 hours
Step-by-step explanation:
45 pages=1.5 hours
300=x
x=300*1.5/45
x=10
First taking into account the if he buys in order.
Brian has 10 choices for the first selection of fish, 9 for the second selection and 8 for the third selection.
Thus you have 10*9*8 = 720 possible ways
However the question did not specify if it is in order. Now counting how many possible orders for each selection you can have
fish 1 , fish 2 , fish 3 or
fish 1 , fish 3 , fish 2 or
fish 2 , fish 1 , fish 3 or
fish 2 , fish 3 , fish 1 or
fish 3 , fish 1 , fish 2 or
fish 3 , fish 2 , fish 1 or
We have 6 order.
dividing the possible ways by the order we have 720 / 60 = 120
The answer is B. 120
