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sineoko [7]
3 years ago
9

Cameron sponsor a fun raiser that 582 people attended he raise $6480 he charged $15 for balcony seats and $10 for crown seats ho

w many people bought balcony seats and how many people bought ground seats
Mathematics
1 answer:
bagirrra123 [75]3 years ago
8 0

Answer:

132 people bought balcony tickets and 450 bout ground tickets

Step-by-step explanation:

let x be balcony and y for ground

x+y=582

15x+10y=6480  solve by adding(subtracting)/eliminating process

multiply first equation by 15 to eliminate x:

15x+15y=8730

15x+10y=6480      subtract

15x+15y-15x-10y=8730-6480

5y=2250

y=2250/5=450

x+y=582

x=582-450=132

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275,301+21,748=297,049
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3 years ago
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MICE is a rhombus. Solve for each missing angle measure.<br><br> &lt;1<br> &lt;2<br> &lt;3
spayn [35]

Answer:

the answer is :

<1=90°

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5 0
2 years ago
The table lists how poverty level income cutoffs​ (in dollars) for a family of four have changed over time. Use the midpoint for
frez [133]

The poverty level cutoff in 1987 to the nearest dollar  was $10787.

<h3>How to find a midpoint?</h3>

The midpoint as the point that divides the line segment exactly in half having two equal segments. Therefore, the midpoint presents the same distance between the endpoints for the line segment. The midpoint formula is: \mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right).

For solving this exercise, first you need plot the points in a chart. See the image.

Your question asks to approximate the poverty level cutoff in 1987 to the nearest dollar using the midpoint formula. Note that the year 1987 is between 1980 and 1990, thus you should apply the midpoint formula from data for this year (1987).

\mathrm{Midpoint\:of\:}\left(1980,8429),\:\left(1990,13145):\quad \left(\frac{1990+1980}{2},\:\:\frac{13145+8429}{2}\right)\\\\ \\

\mathrm{Midpoint\:of\:}\left(1980,8429)\:=\left(\frac{1990+1987}{2},\:\frac{13145+3843}{2}\right)\\ \\ =\left(\frac{3977}{2},\:\frac{21574}{2}\right)

\mathrm{Midpoint\:of\:}\left(1980,8429)\:=\=(\frac{3977}{2},10787)

The answer for your question will be the value that you calculated for the y-coordinate. Then, the poverty level cutoff in 1987 to the nearest dollar  was $10787.

Read more about the midpoint segment here:

brainly.com/question/11408596

7 0
2 years ago
Write a numerical expression for the phrase and simplify the expression. The sum of -6 and -10 increased by 11.
BlackZzzverrR [31]

Answer:

-116

Step-by-step explanation:

5 0
3 years ago
The average mass of an ant is approximately 3 × 10 − 3 grams. The average mass of a giraffe is approximately 2 × 10 3 kilograms.
Vika [28.1K]

Given that average mass of an ant = 3 \times 10^{-3}grams.

Given that average mass of a giraffe = 2 \times 10^{3} Kilograms.

Now we have to find about how many times more mass does a giraffe have than an ant. Before carring out any comparision, we must make both units equal.

Like convert kilogram into gram or gram into kilogram.

I'm going to convert kilogram into gram using formula

1 Kg = 1000 g


So the average mass of a giraffe = 2 \times 10^{3} *10^3 grams.


Now we just need to divide mass of giraffe by mass of ant to find the answer.

\frac{2 \times 10^{3} *10^3 }{3 \times 10^{-3} }

= \frac{2 \times 10^{3} *10^3 *10^{3}}{3  }

= \frac{2 \times 10^{3+3+3}}{3  }

= \frac{2 \times 10^9}{3  }

= \frac{2}{3  } \times 10^9

=666666666.667

Hence final answer is \frac{2}{3  } \times 10^9 which is approx 666666666.667.

3 0
3 years ago
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