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bekas [8.4K]
3 years ago
12

Find the area of a parallelogram with a base of 8 and a height 12 ft

Mathematics
2 answers:
Anuta_ua [19.1K]3 years ago
7 0
Hello!

We must use a certain formula to find the area of a parallelogram. The formula is:

A = bh

Since we have the dimensions, all we need to do is multiply them together:

A = bh

A = 8 × 12

A = 96

ANSWER:

The area of the parallelogram is 96 ft^2.

*Since area is squared, make sure to write a small 2 above "ft"!
Furkat [3]3 years ago
6 0
A = base * height

A = 8*12

A = 96 ft^2
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Simplify the expression:<br><br> –6(–3y + 8) =
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Step-by-step explanation:

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An important tool in archeological research is radiocarbon dating, developed by the American chemist Willard F. Libby.3 This is
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(a) Assuming that Q satisfies the differential equation Q' = -rQ, determine the decay constant r for carbon-14. (b) Find an expression for Q(t) at any time t, if Q(0) = Qo. (c) Suppose that certain remains are discovered in which the current residual amount of carbon-14 is 20% of the original amount. Determine the age of these remains.

Answer:

a) r = (In 2)/(t1/2) = (In 2)/5730 = 0.000121/year

b) Q(t) = Q₀ (e^-rt)

c) Are of the 20% remnant of Carbon-14 = 13301.14 years.

Step-by-step explanation:

Q' = -rQ

Q' = dQ/dt

dQ/dt = -rQ

dQ/Q = -rdt

Integrating the left hand side from Q₀ to Q₀/2 and the right hand side from 0 to t1/2 (half life, t1/2 = 5730 years)

In ((Q₀/2)/Q₀) = -r(t1/2)

In (1/2) = -r(t1/2)

In 2 = r(t1/2)

r = (In 2)/(t1/2) = (In 2)/5730 = 0.000121 /year

b) Q' = -rQ

Q' = dQ/dt

dQ/dt = -rQ

dQ/Q = -rdt

Integrating the left hand side from Q₀ to Q(t) and the right hand side from 0 to t.

In (Q(t)/Q₀) = -rt

Q(t)/Q₀ = e^(-rt)

Q(t) = Q₀ (e^-rt)

c) Q(t) = Q₀ (e^-rt)

Q(t) = 0.2Q₀, t = ? and r = 0.000121/year

0.2Q₀ = Q₀ (e^-rt)

0.2 = e^-rt

In 0.2 = -rt

-1.6094 = - 0.000121 × t

t = 1.6094/0.000121 = 13301.14 years.

Hope this Helps!

5 0
3 years ago
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