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Nastasia [14]
2 years ago
8

On Monday, it took 5 builders 3 and a 1/2 hours to build a wall. An identical wall needs to be built on Tuesday but only 2 build

ers are available. Each builder is paid £9.30 for each hour or part of an hour they work. Work out how much each builder will be paid for the work completed by Tuesday.
Mathematics
1 answer:
alexira [117]2 years ago
6 0
5 \text { builders =} 3 \dfrac{1}{2}  \text { hours }

-------------------------------------------------------
Find 1 worker :
-------------------------------------------------------
1 \text { builders =} 3 \dfrac{1}{2}  \times 5 \text { hours }

1 \text { builders =} \dfrac{35}{2} \text { hours }

-------------------------------------------------------
Find 2 workers :
-------------------------------------------------------
2 \text { builders =} \dfrac{35}{2} \div 2 \text { hours }

2 \text { builders =} \dfrac{35}{4} \text { hours }

2 \text { builders =} 8.75 \text { hours }

-------------------------------------------------------
Find cost of 1 worker :
-------------------------------------------------------
Since they are paid hourly or part of an hour at £9.30.

One builder = £9.30 x 9 = £83.70

-------------------------------------------------------
Answer: Each worker will be paid £83.70.
-------------------------------------------------------


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Peter wants to test an assumption on the number of trees that tested positive for a particular infestation. He decides to focus
LUCKY_DIMON [66]

Answer:

H0 : P ≤ 0.12

H1 : P > 0.12

Step-by-step explanation:

12% = 12/ 100 = 0.12

Given the population proportion, P = 0.12

The claim is the alternative hypothesis, H1 ; which is to test if more than 12% of trees have been infested.

Hence, the alternative hypothesis will be ;

H1 : P > 0.12

The null hypothesis which is the initial truth is always the opposite of the alternative hypothesis, Therefore, we write our null as ;

The null hypothesis ; H0 : P ≤ 0.12

Therefore, we have :

H0 : P ≤ 0.12

H1 : P > 0.12

4 0
2 years ago
HELP ILL GIVE BRAINLIEST!!!!
Setler [38]

Its A i had the same one. Hope it helps.

8 0
3 years ago
The price of a bungalow in 1990 was $850000. If there was a 125% increase in 2000, followed by a 30% decrease in 2013, what was
astra-53 [7]

Answer:

1,338,750$

Step-by-step explanation:

1990 price was 850,000

in 2000

850,000 + 125% = 1,062,500

850,000 + 1,062,500 = 1,912,500

in 2013

1,912,500 - 30% = 573,750

1,912,500 - 573,750 = 1,338,750

6 0
1 year ago
There are 2,000 eligible voters in a precinct. A total of 500 voters are randomly selected and asked whether they plan to vote f
Ann [662]

Answer:

0.7 - 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.647

0.7 + 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.753

And the 99% confidence interval would be given (0.647;0.753).

So the correct answer would be:

a. 0.647 and 0.753

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

The estimated population proportion for this case is:

\hat p = \frac{350}{500}=0.7

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

And replacing into the confidence interval formula we got:

0.7 - 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.647

0.7 + 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.753

And the 99% confidence interval would be given (0.647;0.753).

So the correct answer would be:

a. 0.647 and 0.753

7 0
2 years ago
There are 5,280 feet in a mile. If a cloud is 5.3 miles above the
Ivenika [448]

Answer:

996.2

Explanation:

There are 5,280 feet in a mile. If a cloud is 5.3 miles above the

ground, so you divide 5,280 by 5.3, so it is about 996.2.

7 0
2 years ago
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