PLEASE HELP ASAP !!!

The Falcons had 3 fewer than twice as many Bears players. If the Falcons had 11 players, how many players were on the Bears?

Dmitry [639]

Subtraction, 11-3 is 8
Ps:trick question

3 0

2 years ago

Karen is riding her bike at 4 miles per hour she wants to show this on a graph what should she draw

astraxan [27]

Graph needs to be labeled. I labeled it as shown on picture. It also needs a title. The title can be up to you. :) you can title it “Karen riding her bike”

6 0

3 years ago

Two lighthouses are located 75 miles from one another on a north-south line. If a boat is spotted S 40o E from the northern ligh

yuradex [85]

Answer:

The northern lighthouse is approximately $24.4\; \rm mi$ closer to the boat than the southern lighthouse.

Step-by-step explanation:

Refer to the diagram attached. Denote the northern lighthouse as $\rm N$ , the southern lighthouse as $\rm S$ , and the boat as $\rm B$ . These three points would form a triangle.

It is given that two of the angles of this triangle measure $40^{\circ}$ (northern lighthouse, $\angle {\rm N}$ ) and $21^{\circ}$ (southern lighthouse $\angle {\rm S}$ ), respectively. The three angles of any triangle add up to $180^{\circ}$ . Therefore, the third angle of this triangle would measure $180^{\circ} - (40^{\circ} + 21^{\circ}) = 119^{\circ}$ (boat $\angle {\rm B}$ .)

It is also given that the length between the two lighthouses (length of $\rm NS$ ) is $75\; \rm mi$ .

By the law of sine, the length of a side in a given triangle would be proportional to the angle opposite to that side. For example, in the triangle in this question, $\angle {\rm B}$ is opposite to side $\rm NS$ , whereas $\angle {\rm S}$ is opposite to side ${\rm NB}$ . Therefore:

$\begin{aligned} \frac{\text{length of NS}}{\sin(\angle {\rm B})} = \frac{\text{length of NB}}{\sin(\angle {\rm S})} \end{aligned}$ .

Substitute in the known measurements:

$\begin{aligned} \frac{75\; \rm mi}{\sin(119^{\circ})} = \frac{\text{length of NB}}{\sin(21^{\circ})} \end{aligned}$ .

Rearrange and solve for the length of $\rm NB$ :

$\begin{aligned} & \text{length of NB} \\ =\; & (75\; \rm mi) \times \frac{\sin(21^{\circ})}{\sin(119^{\circ})} \\ \approx\; & 30.73\; \rm mi\end{aligned}$ .

(Round to at least one more decimal places than the values in the choices.)

Likewise, with $\angle {\rm N}$ is opposite to side ${\rm SB}$ , the following would also hold:

$\begin{aligned} \frac{\text{length of NS}}{\sin(\angle {\rm B})} = \frac{\text{length of SB}}{\sin(\angle {\rm N})} \end{aligned}$ .

$\begin{aligned} \frac{75\; \rm mi}{\sin(119^{\circ})} = \frac{\text{length of SB}}{\sin(40^{\circ})} \end{aligned}$ .

$\begin{aligned} & \text{length of SB} \\ =\; & (75\; \rm mi) \times \frac{\sin(40^{\circ})}{\sin(119^{\circ})} \\ \approx\; & 55.12\; \rm mi\end{aligned}$ .

In other words, the distance between the northern lighthouse and the boat is approximately $30.73\; \rm mi$ , whereas the distance between the southern lighthouse and the boat is approximately $55.12\; \rm mi$ . Hence the conclusion.

4 0

2 years ago

7. A bag of M&Ms contains the following distribution of colors:

lys-0071 [83]

Answer:

a) 21/1240 = 0.017

b) 9/1240 = 7.26*10^-3

c) 3/2480 = 1.21*10^-3

Step-by-step explanation:

There are total 32 M&Ms in the bag

a) Probability that all three are blue M&Ms (without replacement)

(9/32)*(8*31)*(7/30) = 21/1240 = 0.017

b) Probability that the first one selected is blue, the second one selected is orange, and the third one selected is red

(9/32)*(6/31)*(4/30) = 9/1240 = 7.26*10^-3

c) Probability that the first two selected are red, and the third one selected is yellow

(4/32)*(3/31)*(3/30) = 3/2480 = 1.21*10^-3

3 0

3 years ago

Please help!!!!!!!!!!

Sunny_sXe [5.5K]

Answer:

From the chapter Playing with numbers

we can define derek has 2×10^2 + 7 × 10^1 + 7× +0^0

as If ABC a number then ABC can be written as 10^2A+10^1B+10^0C

Hope it helps

7 0

2 years ago