Find each sum or difference.(3x^2+2)+(4x^2+3)

Find the midpoint M of the line segment joining the points C=(8,7) and D= (4,-5)

Anon25 [30]

Explanation

We are told to find the midpoint of the line segment. To do so, we will use the formula:

$midpoint=\frac{x_2+x_1}{2},\frac{y_2+y_1}{2}$

In our case

$\begin{gathered} x_1=8,y_1=7 \\ x_2=4,y_2=-5 \end{gathered}$

Substituting the values above

$\begin{gathered} Midpoint=\frac{8+4}{2},\frac{7-5}{2} \\ \\ Midpoint=\frac{12}{2},\frac{2}{2} \\ \\ Midpoint=(6,1) \end{gathered}$

Thus, the midpoint is (6,1)

5 0

1 year ago

The college Physical Education Department offered an Advanced First Aid course last summer. The scores on the comprehensive fina

dmitriy555 [2]

Answer:

a)

b. Joel

c. Juan

d. Linda

b)

b. Joel

c)

a. Jan

f.Susan

d)

a. Jan: 140

b. Joel: 156

c. Juan: 196

d. Linda: 191

e. Robert: 183

f. Susan: 110

Step-by-step explanation:

Z-score:

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean, positive z-scores are above the mean, negative are below the mean and 0 is the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Question a:

Robert, Juan and Linda had positive z-scores, so they scored above the mean, and the correct options are c,d,e.

(b) Which of these students scored on the mean?

Joel, which had a z-score of 0, so the correct option is b.

(c) Which of these students scored below the mean?

Jan and Susan had negative z-scores, so them, options a and f.

Question d:

We have that $\mu = 156, \sigma = 24$ , so we have to find X for each student.

Jan:

Z = -0.65. So

$Z = \frac{X - \mu}{\sigma}$

$-0.65 = \frac{X - 156}{24}$

$X - 156 = -0.65*24$

$X = 140$

b. Joel

Z = 0, so:

$Z = \frac{X - \mu}{\sigma}$

$0 = \frac{X - 156}{24}$

$X - 156 = 0*24$

$X = 156$

c. Juan

Z = 1.66, so:

$Z = \frac{X - \mu}{\sigma}$

$1.66 = \frac{X - 156}{24}$

$X - 156 = 1.66*24$

$X = 196$

d. Linda

Z = 1.46. So

$Z = \frac{X - \mu}{\sigma}$

$1.46 = \frac{X - 156}{24}$

$X - 156 = 1.46*24$

$X = 191$

e. Robert

Z = 1.11. So

$Z = \frac{X - \mu}{\sigma}$

$1.11 = \frac{X - 156}{24}$

$X - 156 = 1.11*24$

$X = 183$

f. Susan

Z = -1.9. So

$Z = \frac{X - \mu}{\sigma}$

$-1.9 = \frac{X - 156}{24}$

$X - 156 = -1.9*24$

$X = 110$

8 0

3 years ago

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Zarrin [17]

Answer:

third option

Step-by-step explanation:

8 0

3 years ago

A'Reana earns a weekly allowance for doing chores around the house and for keeping all of her grades above a C. During a particu

JulsSmile [24]

Answer:

Answer: A'Reana's weekly allowance is $100

Step-by-step explanation:

Backward Solution

To solve some problems, we can work backward, using the inverse operations, to arrive at the solution.

The problem explains a sequence of expenses A'Reana does with her weekly allowance. In the end, she had $37.50.

That final balance came when she last spent $7.50 on a pizza. Thus, before that, she had $37.50+$7.50=$45

This balance is half of her previously remaining money. The other half was spent on a new shirt. Thus she had 2*$45=$90.

Those $90 were left after she gave $10 to her friend Taylor, thus, the initial money was $90+$10 = $100

Answer: A'Reana's weekly allowance is $100

3 0

3 years ago

Use the distributive property to expand the following expression (9m-6)7 please help

Drupady [299]

Answer:2/3

Step-by-step explanation:

Simplifying

(9m + -6) * 7 = 0

Reorder the terms:

(-6 + 9m) * 7 = 0

Reorder the terms for easier multiplication:

7(-6 + 9m) = 0

(-6 * 7 + 9m * 7) = 0

(-42 + 63m) = 0

Solving

-42 + 63m = 0

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '42' to each side of the equation.

-42 + 42 + 63m = 0 + 42

Combine like terms: -42 + 42 = 0

0 + 63m = 0 + 42

63m = 0 + 42

Combine like terms: 0 + 42 = 42

63m = 42

Divide each side by '63'.

m = 0.6666666667

Simplifying

m = 0.6666666667=2/3 when simplified

7 0

3 years ago

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Find each sum or difference.(3x^2+2)+(4x^2+3)​

Find each sum or difference.(3x^2+2)+(4x^2+3)