A --------¢ D
B --------¢ E
C --------¢ F
Just match like this buddy.
To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
Answer:
i think this is what you mean:90 + 7.93
Step-by-step explanation:
If solving for y:
→ 2x + y = 8
→ Take away 2x from both sides
→ y = 8 - 2x
If solving for x:
→ 2x + y = 8
→ Take away y from both sides
→ 2x = 8 - y
→ Divide both sides by 2
→ x =