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3 years ago

Solve the following for x please!

Mathematics

2 answers:

STatiana [176]3 years ago

4 0

Answer:

x = -4

Step-by-step explanation:

It is often easiest to eliminate fractions first. Multiplying by the least common denominator (6), you have ...

2x -1 = 3(x +1)

2x -1 = 3x +3 . . . eliminate parentheses

-4 = x . . . . . . . . add -2x-3 to both sides

Check

(2(-4) -1)/6 = -9/6 = (-4+1)/2 = -3/2 . . . . true

VMariaS [17]3 years ago

3 0

Step-by-step explanation:

First, cross multiply.

2(2x-1)=6(x+1)

Then, use distributive property and multiply

4x-2=6x+6

Then, subtract 4x from 6x and subtract 6 from -2

-8=2x

Divide

-4=x

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3 years ago

solve for a dairy needs 275 gallons of milk containing 5% butterfat. how many gallons each of milk containing 7% butterfat and m

Kazeer [188]

X = gallons of the 7% butterfat milk

y = gallons of the 2% butterfat milk

now, we'll be adding "x" gallons of the 7% one, but we know that, is really "x" gallons, but only 7% of it is butterfat, the rest is water and other subtances.

so, in "x" gallons, how many gallons is butterfat only anyway? namely, what is 7% of "x"? well, (7/100) * x, or 0.07x.

likewise, how many gallons of butterfat are in the 2% one? well, (2/100) * "y" or 0.02y.

we know that, whatever "x" and "y" add up to 275 gallons, thus x + y = 275.

we also know that, the butterfat amounts add up to the same butterfat in the 275 gallons, thus

$\bf \begin{array}{lccclll}
&\stackrel{gallons}{amount}&\stackrel{butterfat~\%}{quantity}&\stackrel{butterfat~gallons}{quantity}\\
&------&------&------\\
\textit{7\% butterfat milk}&x&0.07&0.07x\\
\textit{2\% butterfat milk}&y&0.02&0.02y\\
--------&------&------&------\\
mixture&275&0.05&13.75
\end{array}$

$\bf \begin{cases}
x+y=275\implies \boxed{y}=275-x\\
0.07x+0.02y=13.75\\
----------\\
0.07x+0.02\left( \boxed{275-x} \right)=13.75
\end{cases}
\\\\\\
0.07x-0.02x+5.50=13.75\implies 0.05x=8.25
\\\\\\
x=\cfrac{8.25}{0.05}\implies x=165$

how much will it be of the 2% milk? well, y = 275 - x.

7 0

3 years ago