Answer:
-1.
Step-by-step explanation:
First find the derivative of f(x):
f'(x) = -3x^2 + 12x - 9 = 0 for a maximum or minimum.
-3(x^2 - 4x + 3) = 0
(x - 1)(x - 3) = 0
x = 1, 3.
To find which gives a relative maximum we find the second derivative:
f"(x) = -6x + 12
When x = 1 f"(x) = 6, positive.
when x = 3, f"(x) = -6, negative.
So x = 3 gives a maximum value of f(x).
f(3) = -(3)^3 + 6*(3)^2 - 9(3) - 1 = -1 (answer).
Answer:
Can I see it actually?
Step-by-step explanation:
Answer:
-6 , thinks this is the answer
Step-by-step explanation:
F(-3)= 2(-3) = 6
Is it
d-(2.8/0.2)=-14
or
(d-2.8)/0.2=-14
?
Answer:
f(x) = 2x
Step-by-step explanation:
Remark
What I'm about to do is probably not the best way to do this question, but it is right. The plan is to take out a common factor on the right of f(x - 2) and then derive f(x) from that.
Solution
- f(x - 2) = 2x - 4 Take out a common factor on the right of f(x -2)
- f(x - 2) = 2(x - 2) Now what that means is that in the original equation, wherever you saw an x, you put in x - 2. So the original equation must have been
Check
- f(x) = 2x To check this put x - 2 back in
- f(x - 2) = 2(x -2) Remove the brackets.
- f(x - 2) = 2x - 4 which is what it should be.
