There are 600 students including the seventh and eighth graders at the party.
This problem uses the concept of percentages to define the conditions that are laid in front of us.
Let the original number of students be S , and the number of seventh graders be = 0.60S
We know that percent is used to convey the mathematical term of a fraction multiplied by 100.
Total students after 20 eighth graders arrive = S + 20
And we have that
Number of seventh graders / total number of students = 58%
.60S / [ S + 20 ] = .58 we multiply both sides by S + 20
0.60S =0 .58 [ S + 20]
.60S = .58S + 11.6 we subtract 0.58S from both the sides
0.02S = 11.6 we divide both the sides by .02
S = 11/6 / 0.02 = 580
So the total number of students = 580 + 20 = 600 .
Hence there are 600 students at the party at that time.
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39.5 i am pretty suree of it :P
Answer:
163
Step-by-step explanation:
Given the following :
Number of visitors on Friday = 3,260
Number increased by 15% on Saturday
Projected percentage increase on Saturday = 20%
Actual percentage increase in number of visitors = 15%
Number of visitors on Saturday :
(100 + 15)% × 3260
115% * 3260
(115/100) * 3260
= 3749 visitors
Projected percentage increase = 20%
Projected number:
((100 + 20)% * 3260
120% * 3260
(120/100) * 3260
= 3912
Difference : (3912 - 3749) = 163
