Johns total at the deli is $ 7.58
<u>Solution:</u>
Given, John went to the deli on his lunch hour he bought 1.3 lbs of roast beef and 0.6 lbs of cheese both were on sale for $3.99 per pound.
We have to find the nearest cent how much was Johns total at the deli
Now, we know that, total cost = cost of beef + cost of cheese
Total cost = amount of beef bought 
cost of beef per pound + amount of cheese bought cost of cheese per pound
Total amount = 1.3 3.99 + 0.6 3.99
Total amount = 3.99(1.3 + 0.6) = 3.99 x 1.9
Total amount = 7.581
Hence, the total amount was $7.58
Answer:a) L.C.M OF 2,3,5 is 30
THEREFORE=60/30+15/30÷10/30-6/30
=60/30+15/30×30/10-6/30(DMAS)
=60/30+3/2-6/30
=60+45/30 -6/30(ADDITION FIRST THEN SUBTRACTION.
=105/30-6/30
=105-6/30
=99/30
=33/10
b)(3+1/2)÷(2-1/2)=L.C.M IS 2,=(6+1/2)÷(4-1/2)=7/2÷3/2=7/3
124+124=248 360-248=112 112\2=56
Since you can spend all but 20%, then you can spend the rest, namely the 80%.
whatever% of anything is just (whatever/100) * anything.
therefore, 80% of 225 is then (80/100) * 225, that much.
When something has a negative power you must move it to the denominator to give it a positive power therefore this would then turn into 1/[(5/4)^4] to simplify this (5/4)^4 would be (25/16)(25/16) then finally (625/256) so it would then look like this 1/(625/256) in order to not have a fraction in the denominator you would multiply; 1 x (256/625) which is 256/625.
