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polet [3.4K]
3 years ago
14

28. Solve for x.

Mathematics
1 answer:
bija089 [108]3 years ago
5 0

Answer:

The value of x is 5 , - 5

Step-by-step explanation:

Given as :

Log_{2}(x + 3) + Log_{2}(x - 3) = 4

Now, <u>from log property</u>

Log_{b}m + [tex]Log_{b}n = [tex]Log_{b}(m × n)[tex]Log_{2}(x + 3) + Log_{2}(x - 3) = Log_{2}( (x + 3) × (x - 3) ) [tex]Log_{2}( (x + 3) × (x - 3) ) = 4Again  [tex]Log_{a}b = xSo , b = [tex]a^{x}

So,  (x + 3) × (x - 3) = 2^{4}

Or,  x² - 9 = 16

or,  x² = 25

∴  x = \sqrt{25}

I.e x = \pm 5

Hence the value of x is 5 , - 5  Answer

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What’s the mean , median , and mode of 89 , 76 , 89 , 89 , 100 , 71 , 80
S_A_V [24]

Answer:

Mean = 84.9

Median = 89

Mode = 89

Step-by-step explanation:

89 , 76 , 89 , 89 , 100 , 71 , 80

First, we need to arrange in either ascending or descending order. In this case, let us arrange in ascending order:

71, 76, 80, 89, 89, 89, 100

1. The mean is simply the sum of all the variables divided by the number of variables

Mean = (71+76+80+89+89+89+100)/7

Mean = 594/7

Mean = 84.9

2. Median is the middle term of the distribution

Median = 89

3. Mode is the variable with the highest frequency i.e the variable that appears the most

Mode = 89

7 0
4 years ago
Lee pays $72 in advance on his account at the movie store. Every time he rents a movie, $4 is deducted from his account for ever
lapo4ka [179]
So it would be,
y = 72 - 4x
y is the total money that is left on the account and x isthe movies rented. after renting 4 movies it would be,

y = 72 - 4(4)
y = 72 - 16
y = 56

So there are $56 left in the account after renting 4 movies.
3 0
4 years ago
25% of the 483 people at the school fair are age 6 and under. Estimate how many people are over the age of 6?
Anika [276]
25%*483=0.25*483=120.75
About 121 people at the fair were under the age of 6.
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Find the zeros of the function h(x)=x^2-5x-50 by factoring
lukranit [14]
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When two variables have a positive linear correlation, the dependent variable increases as the independent variable increases. So when the independent variable decreases, the dependent variable decreases as well. Both variables decrease and increase simultaneously.
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