0.3(3 - 0.5)
= 0.3(2.5)
= 0.75
Solution: The given problem is a binomial distribution.
The probability that a team member receives a scholarship is 
Therefore, the given problem follows binomial with n = 5 and p = 0.6667
Now the probability that 4 of 5 players selected are on scholarship is:



Therefore, the probability that 4 of 5 players selected are on scholarship is 0.329
1 would be the right answer !!!!!!!!!!!!!!!!!!!!!