Answer:
Please see attached image and all steps below for both parts
Step-by-step explanation:
Task 1
The following system of equations includes a linear equation and a quadratic one:

it can be solved by using substitution in the second equation of the variable "y" by the linear expression of the first equation:

and this product of two factors will e zero when either factor is zero, that is: when x = 0, or when x = 9 [to make zero the binomial(x - 9)]
There are two solutions: x = 0 and x = 9.
When we graph both expressions in the system, we see that the line intercepts the parabola at the points (0, 2) and (9, 11). See attached image.
Task 2
Part 1:
Let's pick 30 as a number larger than 25. 30 can be written as 40 - 10
So we can use:

to calculate its square.
Part 2:
let's choose a=9 and b=10 so we use:

I hope this helps you
x-3x= -4
-2x= -4
x=2
y= -3.2
y= -6
Log(3^2)+log(5)=log(x)
9*5=x
x=45
Answer: h = 190.
Step-by-step explanation: You have to use the reverse so, the opposite of subtraction is addition, so 156 + 34 = 190. 190 which is the "h" 190 - 156 = 34
B 23%
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