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3 years ago

And this problem your multiplying 12 by 6 was 12 called in this math problem

1 answer:

5 0

To multiply one number ( a multiplicand ) by another ( a multiplier ) means to repeat a multiplicand as an addend times. The result of multiplying is called a product. The operation of multiplication is written as: 12 x 6, or 12 * 6

Multiply 12 by 6

6 is called the Multiplier

12 is called the Multiplicand

72 is called the Product

Therefore, a multiplicand and a multiplier are called factors or multipliers.

Hope that helps!!!! : )

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Which is the greatest rational number? A. 3 2/7 B. 3 1/4 C. 3.31 D. 3.36

lana [24]

Answer:

Step-by-step explanation:

3 1/4 = 3.25

3 2/7 = 3.29

3.29>3.25

3.31>3.29

3.36>3.31

so the answer is D.

4 0

3 years ago

2x+5y=46 5x+3y=58 what are the x and y values

nadya68 [22]

(X,y)=(8,6)
Step by step explanation:

3 0

3 years ago

Refer to Exercise 3.122. If it takes approximately ten minutes to serve each customer, find the mean and variance of the total s

garri49 [273]

Answer

a. The expected total service time for customers = 70 minutes

b. The variance for the total service time = 700 minutes

c. It is not likely that the total service time will exceed 2.5 hours

Step-by-step explanation:

This question is incomplete. I will give the complete version below and proceed with my solution.

Refer to Exercise 3.122. If it takes approximately ten minutes to serve each customer, find the mean and variance of the total service time for customers arriving during a 1-hour period. (Assume that a sufficient number of servers are available so that no customer must wait for service.) Is it likely that the total service time will exceed 2.5 hours?

Reference

Customers arrive at a checkout counter in a department store according to a Poisson distribution at an average of seven per hour.

From the information supplied, we denote that

$X=$ Customers that arrive within the hour

and since $X$ follows a Poisson distribution with mean $\alpha$ = 7

Therefore,

$E(X)= 7$

$& V(X)=7$

Let $Y =$ the total service time for customers arriving during the 1 hour period.

Now, since it takes approximately ten minutes to serve each customer,

$Y=10X$

For a random variable $X$ and a constant $c$ ,

$E(cX)=cE(X)\\V(cX)=c^2V(X)$

Thus,

$E(Y)=E(10X)=10E(X)=10*7=70\\V(Y)=V(10X)=100V(X)=100*7=700$

Therefore the expected total service time for customers = 70 minutes

and the variance for serving time = 700 minutes

Also, the probability of the distribution $Y$ is,

$p_Y(y)=p_x(\frac{y}{10} )\frac{dx}{dy} =\frac{\alpha^{\frac{y}{10} } }{(\frac{y}{10})! }e^{-\alpha } \frac{1}{10}\\ =\frac{7^{\frac{y}{10} } }{(\frac{y}{10})! }e^{-7 } \frac{1}{10}$

So the probability that the total service time exceeds 2.5 hrs or 150 minutes is,

$P(Y>150)=\sum^{\infty}_{k=150} {p_Y} (k) =\sum^{\infty}_{k=150} \frac{7^{\frac{k}{10} }}{(\frac{k}{10})! }.e^{-7} .\frac{1}{10} \\=\frac{7^{\frac{150}{10} }}{(\frac{150}{10})! } .e^{-7}.\frac{1}{10} =0.002$

0.002 is small enough, and the function $\frac{7^{\frac{k}{10} }}{(\frac{k}{10} )!} .e^{-7}.\frac{1}{10}$ gets even smaller when $k$ increases. Hence the probability that the total service time exceeds 2.5 hours is not likely to happen.

3 0

3 years ago

-x ≥ 23 What is the answer?

juin [17]

Answer:

x is less than or equal to -23

Step-by-step explanation:

-x is greater than or equal fo 23 divide negative on both sides

x is less than or equal to -23

(srry i don't have the inequality signs)

5 0

3 years ago

PLEASE HELP. zoom in to remove blur

AleksAgata [21]

Answer:

It's A

Step-by-step explanation:

It's just moving the equation to the right 4 units. There's no stretch, compression, or reflection.

5 0

2 years ago