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soldier1979 [14.2K]
4 years ago
13

Find a unit vector in the direction of the vector left bracket Start 3 By 1 Matrix 1st Row 1st Column negative 8 2nd Row 1st Col

umn 7 3rd Row 1st Column negative 2 EndMatrix right bracket
−8
7
−2
.

A unit vector in the direction of the given vector is left bracket Start 3 By 1 Matrix 1st Row 1st Column nothing 2nd Row 1st Column nothing 3rd Row 1st Column nothing EndMatrix right bracket

?
?
?
.

​(Type exact​ answers, using radicals as​ needed.)
Mathematics
1 answer:
MrRissso [65]4 years ago
5 0

Answer:

\left[\begin{array}{c}-\frac{8}{\sqrt{117} } \\\frac{7}{\sqrt{117} }\\\frac{2}{\sqrt{117} }\end{array}\right]

Step-by-step explanation:

We are required to find a unit vector in the direction of:

\left[\begin{array}{c}-8\\7\\2\end{array}\right]

Unit Vector, \hat{a}=\dfrac{\overrightarrow{a}}{|\overrightarrow{a}|}

The Modulus of \overrightarrow{a} =\sqrt{(-8)^2+7^2+(-2)^2}=\sqrt{117}

Therefore, the unit vector of the matrix is given as:

\left[\begin{array}{c}-\frac{8}{\sqrt{117} } \\\frac{7}{\sqrt{117} }\\\frac{2}{\sqrt{117} }\end{array}\right]

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Answer:

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Step-by-step explanation:

The discriminant is the following equation:

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4 0
3 years ago
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lesya692 [45]

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Step-by-step explanation:

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Use the discriminate to determine the number and the nature of the solutions of the giving equation.
PolarNik [594]

Answer:

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Step-by-step explanation:

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Since b^2 -4ac = 256 we have 2 real distinct root roots

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